Wilbur ran 27.6 miles more than Totsakan

Please help me i dont know how to do this

Vaselesa [24]

Answer:

I can't give you an exact answer because the graph is too blurry.

Step-by-step explanation:

however I can tell you how to answer it,

so all you need to do is take each point on the graph and add 2 to the y coordinate and add 5 to the x. you so this because it says up and to the right. hope this helps

5 0

4 years ago

Each student wrote a two step equation. peter wrote the equation 4x - 2 =10, and andres wrote the equation 16x - 8 = 40. the tea

Kitty [74]

4x-2=10
answer is 3
16x-8=40
answer is 2
they are all even numbers. it is all divisible.by 4
I think

7 0

4 years ago

Tina’s house is located at point (5,4). What quadrant is Tina’s house in?

DiKsa [7]

Answer:

Tina's house located at point (5,4) is in Quadrant |.

Step-by-step explanation:

If both numbers in the parenthesis are positive, it's put in Quadrant |.

(You can also look up a graph quadrant divider and it will show you)

6 0

3 years ago

Ocean tides can be modeled by a sinusoidal function. Suppose that there is a low and high tide every 12 hours, and that high tid

USPshnik [31]

Answer:

(a) $y=5sin(\frac{\pi}{6}(x+2))+5$

(b) 7.5ft above the low tide.

Step-by-step explanation:

(a) To find the function that computes the height of the tide, you need to select the form of the sinusoidal function. For example, use the form:

$y=Asin(B(x-C))+D$

Where A is the amplitude, B the frequency, C the phase shift and D the vertical shift.

The amplitude is half the distance between the highest and the lowest tide:

$A=10/2=5ft$

The frequency is related to the period T by:

$B=\frac{2\pi}{T}$

The period is 12 hours, then

$B=\frac{2\pi}{12}=\frac{\pi}{6}$

The high tide is at 1:00 a.m. and 1:00 p.m. , this is the moment when $sin(B(x-C))=1$ , if $sin(\frac{\pi}{2})=1$ then $B(x-C)$ must be equal to $\frac{\pi}{2}$ when $x=1$ :

$B(x-C)=\frac{\pi}{2}\\\frac{\pi}{6}(1-C)=\frac{\pi}{2}\\\frac{1}{6}(1-C)=\frac{1}{2}\\(1-C)=\frac{6}{2}\\-C=3-1\\C=-2$

The vertical shift is the sum of the lowest value, the height of the low tide ( $lt$ ) and the amplitude:

$D=5+lt$

The function is:

$y=5sin(\frac{\pi}{6} (x+2))+5+lt$

Because the function must be the height above low tide height, subtract this heigh from the function:

$y=5sin(\frac{\pi}{6} (x+2))+5+lt-lt$

$y=5sin(\frac{\pi}{6} (x+2))+5$

(b) Use x=11 in the function

$y=5sin(\frac{\pi}{6} (11+2))+5=2.5+5=7.5ft$ above the low tide.

3 0

4 years ago

A data set has 40 data points. Enter values to answer each of the questions below.

alukav5142 [94]

When the number of data points is odd the formula to find the Ranking of the Median is (n+1)/2, When the number of data points is even the ranking of the Median will be the AVERAGE of n/2 + n/2 +1, where n is the number of data points.

In our case the ranking of the Median is the average (20+21)/2 = 20.5.

1- How many points are below the Median =20

Lower half = 20, Upper half = 20 & Median = 20.5 (Don't forget Median is the ranking of data points).

Again the 1st Quartile is at 10.5, so 10 data points are below the 1st Quartile

and 20 points are between Q1 & Q3

5 0

3 years ago

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