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wel
3 years ago
13

Solve: ln(x – 3) = ln(7x – 23) –  ln(x + 1)

Mathematics
1 answer:
Dvinal [7]3 years ago
8 0
Formula\ for\ lagarythm:\\
log_ab=c\ \ \ ----> a^c=b\\\\Base\ of\ ln \ is\ e=2,7\\\\ln(x-3)=ln(7x-23)-ln(x+1)\\\\
ln(x-3)=ln(\frac{7x-23}{x+1})\ \ \ | subtract\ ln(\frac{7x-23}{x+1})\\\\
ln(\frac{\frac{7x-23}{x+1}}{x-3})=0\\\\
ln(\frac{7x-23}{(x+1)(x-3)})=0\\\\
2,7^0=\frac{7x-23}{(x+1)(x-3)}\\\\
1=\frac{7x-23}{(x+1)(x-3)}\ \ \ | multiply\ by\ (x+1)(x-3)\\\\
(x+1)(x-3)=7x-23\\\\
x^2-3x+x-3=7x-23\\\\
x^2-9x-26=0\\\\x=\frac{1}{2}(9-\sqrt{185})\ \ or\ \ x=\frac{1}{2}(9+\sqrt{185})

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e-lub [12.9K]
Let the number of minutes be = x.

Cost per minute = 11 cents = 0.11

Phone Bill = Monthly fee  +    0.11* x 

Substituting from the question

20.82 = 3 + 0.11x

3 + 0.11x = 20.82

0.11x = 20.82 - 3

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<span>Lamar was billed for 162 minutes.</span>
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3 years ago
Suppose u=&lt;2,−1&gt; and v=&lt;1,−8&gt; are two vectors that form the sides of a parallelogram. Then the lengths of the two di
tigry1 [53]
| u | = √(2² + (-1²)) = √5
| v | = √ ( 1² + (-8)² = √65
cos (u,v) = ( u * v ) / (| u | * | v |) =
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The length of a larger diagonal:
d 1² = | u |² + 2 |u| |v| + | v |² = 5 + (2 √5 √65 * 10 / √5 √65 )+65
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Answer:
The lengths of the diagonals are: 3√10 and 5√2 .
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3 years ago
Which statement is true about the number of faces on any prism?
antiseptic1488 [7]
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What would have to be done to put 3x (2x - 7) =9 in standard form? Group of answer choices
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Step-by-step explanation:

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Musya8 [376]

Answer:

y + 2 = \frac{2}{3}(x - 1)

Step-by-step explanation:

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y - b = m(x - a)

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y - 4 = \frac{2}{3}(x - 3) ← is in point- slope form

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