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3 years ago

You have a box of 50 cookies. 18% of them are sugar cookies. How many cookies in the box are not sugar cookies?

Mathematics

2 answers:

Andrei [34K]3 years ago

5 0

Answer:

41 cookies in the box are not sugar cookies

Step-by-step explanation:

First, find what percentage of the total cookies <u>aren't</u> sugar cookies. If 18% are, then the amount that aren't is:

100% - 18% = 82%

Since 82% of the cookies aren't sugar cookies, multiply 82% by 50 to find the amount of cookies that aren't sugar cookies:

50 * 82% = 41

Agata [3.3K]3 years ago

5 0

Answer:

Step-by-step explanation:

first work out how many of the total cookies are 1%. To calculate this, divide the total by 100

50 ÷ 100 = 0.5 (1% of the cookies is 1/2 a cookie)

As 18% of these cookies are sugar cookies, multiply the 1% by 18

0.5 x 18 = 9 (9 of the cookies are sugar cookies)

To work out how many are NOT sugar cookies, subtract the sugar cookies from the total

50 - 9 = 41

∴41 of the cookies were NOT sugar cookies

I hope this helped :-)

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which of the following is equivalent to 3 sqrt 32x^3y^6 / 3 sqrt 2x^9y^2 where x is greater than or equal to 0 and y is greater

Nutka1998 [239]

Answer:

$\frac{\sqrt[3]{16y^4}}{x^2}$

Step-by-step explanation:

The options are missing; However, I'll simplify the given expression.

Given

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$

Required

Write Equivalent Expression

To solve this expression, we'll make use of laws of indices throughout.

From laws of indices $\sqrt[n]{a} = a^{\frac{1}{n}}$

So,

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$ gives

$\frac{(32x^3y^6)^{\frac{1}{3}}}{(2x^9y^2)^\frac{1}{3}}$

Also from laws of indices

$(ab)^n = a^nb^n$

So, the above expression can be further simplified to

$\frac{(32^\frac{1}{3}x^{3*\frac{1}{3}}y^{6*\frac{1}{3}})}{(2^\frac{1}{3}x^{9*\frac{1}{3}}y^{2*\frac{1}{3}})}$

Multiply the exponents gives

$\frac{(32^\frac{1}{3}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

Substitute $2^5$ for 32

$\frac{(2^{5*\frac{1}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

$\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

From laws of indices

$\frac{a^m}{a^n} = a^{m-n}$

This law can be applied to the expression above;

$\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$ becomes

$2^{\frac{5}{3}-\frac{1}{3}}x^{1-3}*y^{2-\frac{2}{3}}$

Solve exponents

$2^{\frac{5-1}{3}}*x^{-2}*y^{\frac{6-2}{3}}$

$2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}}$

From laws of indices,

$a^{-n} = \frac{1}{a^n}$ ; So,

$2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}}$ gives

$\frac{2^{\frac{4}{3}}*y^{\frac{4}{3}}}{x^2}$

The expression at the numerator can be combined to give

$\frac{(2y)^{\frac{4}{3}}}{x^2}$

Lastly, From laws of indices,

$a^{\frac{m}{n} = \sqrt[n]{a^m}$ ; So,

$\frac{(2y)^{\frac{4}{3}}}{x^2}$ becomes

$\frac{\sqrt[3]{(2y)}^{4}}{x^2}$

$\frac{\sqrt[3]{16y^4}}{x^2}$

Hence,

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$ is equivalent to $\frac{\sqrt[3]{16y^4}}{x^2}$

8 0

3 years ago

Nine more than four times a number is the same as one less than twice the number find the number

klio [65]

4x + 9 = 2x - 1
4x - 2x = -1 - 9
2x = -10
x = -10/2
x = -5 <===

8 0

3 years ago

A helicopter is flying directly above a submarine at a position of 125 feet above sea level. The submarine is located at -70 fee

Vlad [161]

Answer:

125+70

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Lisa had 1750 stamps. Mark had 480 fewer stamps than Lisa. Lisa gave some stamps to Mark. Now Mark has three times as many stamp

notka56 [123]

> How many stamps did Mark have at first?

We know that Lisa has 1750 stamps and Mark has 480 fewer than this, therefore subtract 480 from 1750 to get the number of stamps that Mark had at first:

1750 – 480 = 1270 stamps

> How many stamps does Lisa have now?

Let us say that x = the number of stamps that Lisa gave to Mark, therefore we can create the equation:

Mark = 3 * Lisa

480 + x = 3 (1750 – x)

480 + x = 5250 – 3x

4x = 4770

x = 1,192.50 stamps

So Lisa has now left with:

1750 – 1192.50 = 557.5 stamps ~ 557 stamps or 558

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3 years ago

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maks197457 [2]

Me! I can help you.

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3 years ago