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zubka84 [21]
3 years ago
15

Please find attached the question

Mathematics
1 answer:
Dima020 [189]3 years ago
8 0

Answer:

Step-by-step explanation:

We will use the area of the circle to find the radius of the circle since that's all that that is useful for! If the area of the circle is 56 cm squared, then

56=\pi r^2  and

\frac{56}{\pi}=r^2  and

17.82535363=r^2 so

r = 4.222 cm

Now that we know that, we will use that.  But first, if we have a square circumscribed in a circle, then we know that from the center of the circle to any of the vertices of the square is the radius of the circle, 4.222. If we split that square into 4 triangles, pull one of those triangles out, we have a right triangle...45-45-90 to be specific.  Just for the sake of argument, put the 90 degree angle as the vertex angle of that right triangle and then split THAT triangle in half by dropping an altitude from the vertex angle to the base.  We still have a 45-45-90 triangle, but now the vertex angle is 45, one of the base angles is 90, and the other base angle is 45.  The hypotenuse of that triangle is the length of the radius we just found.  If the base angle is 45 and the hypotenuse is 4.222, we can use right triangle trig to find the length of the base of that triangle which, consequently, is half of the length of x, our unknown.

sin(45)=\frac{x}{4.222} and

4.222 sin(45) = x so

x = 2.9854

But don't forget that that x is only half the length of one of the sides of the square.  So multiply it by 2 to get that the side length, which is x, is

x = 5.97

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Zielflug [23.3K]

STEP - BY - STEP EXPLANATION

What to find?

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Given:

(4, 3)

⇒(x, y) = (4, 3)

Step 1

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Step 2

Substitute the values into the trig. ratio formula below.

tan\theta=\frac{opposite}{adjacent}

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Step 3

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let h be the hypotenuse side.

\begin{gathered} h^2=4^2+3^2 \\  \\ =16+9 \\  \\ =25 \\  \\ h=5 \end{gathered}

Hence, hypotenuse = 5

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Substitute the values into the formula below:

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Will Mark Brainiest!!! Simplify the following:
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Answer:

1.B

2.A

3. B

Step-by-step explanation:

1. \frac{x+5}{x^{2} + 6x +5 }

We have the denominator of the fraction as following:

x^{2} + 6x + 5 \\= x^{2} + (1 + 5)x + 5\\= x*x + 1x + 5x + 5*1\\= x ( x + 1) + 5(x + 1)\\= (x + 1) (x + 5)

As the initial one is a fraction, so that its denominator has to be different from 0.

=> (x^{2} +6x+5) ≠ 0

⇔ (x +1) (x +5) ≠ 0

⇔ (x + 1) ≠ 0; (x +5) ≠ 0

⇔ x ≠ -1; x ≠ -5

Replace it into the initial equation, we have:

\frac{x+5}{x^{2} + 6x +5 } = \frac{x+5}{(x+1)(x+5)}

As (x+5) ≠ 0; we divide both numerator and denominator of the fraction by (x +5)

=> \frac{x+5}{x^{2} + 6x +5 } = \frac{x+5}{(x+1)(x+5)} = \frac{1}{x+1}

So that \frac{x+5}{x^{2} + 6x +5 } = \frac{1}{x+1} with x ≠ 1; x ≠ -5

So that the answer is B.

2. \frac{(\frac{x^{2} -16 }{x-1} )}{x+4}

As the initial one is a fraction, so that its denominator has to be different from 0

=> x + 4 ≠ 0

=> x ≠ -4

As \frac{x^{2}-16 }{x-1} is also a fraction, so that its denominator (x-1) has to be different from 0

=> x - 1 ≠ 0

=> x ≠ 1

We have an equation: x^{2} - y^{2} = (x - y ) (x+y)

=> x^{2} - 16 = x^{2} - 4^{2} = (x -4)  (x +4)

Replace it into the initial equation, we have:

\frac{(\frac{x^{2} -16 }{x-1} )}{x+4} \\= \frac{x^{2} -16 }{x-1} . \frac{1}{x + 4}\\= \frac{(x-4)(x+4)}{x-1}. \frac{1}{x + 4}

As (x + 4) ≠ 0 (proven above), we can divide both numerator and the denominator of the fraction by (x +4)

=> \frac{(x-4)(x+4)}{x-1} .\frac{1}{x+4} =\frac{x-4}{x-1}

So that the initial equation is equal to \frac{x-4}{x-1} with x ≠-4; x ≠1

=> So that the correct answer is A

3. \frac{x}{4x + x^{2} }

As the initial one is a fraction, so that its denominator (4x + x^2) has to be different from 0

We have:

(4x + x^2) = 4x + x.x = x ( x + 4)

So that:  (4x + x^2) ≠ 0 ⇔ x ( x + 4 ) ≠ 0

⇔ \left \{ {{x\neq 0} \atop {(x+4)\neq0 }} \right.  ⇔ \left \{ {{x\neq 0} \atop {x \neq -4 }} \right.

As (4x + x^2) = x ( x + 4) , we replace this into the initial fraction and have:

\frac{x}{4x + x^{2} } = \frac{x}{x(x+4)}

As x ≠ 0, we can divide both numerator and denominator of the fraction by x and have:

\frac{x}{x(x+4)} =\frac{x/x}{x(x+4)/x} = \frac{1}{x+4}

So that \frac{x}{4x+x^{2} }  = \frac{1}{x+4} with x ≠ 0; x ≠ -4

=> The correct answer is B

3 0
3 years ago
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