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3 years ago

What's the answer for those two questions and explain how you get that answer

Mathematics

2 answers:

Gemiola [76]3 years ago

5 0

3. C

(For A, they can't have the greater Range, because Range is shown by the Dots at the furthest ends of the lines. For B, tbh I don't actually know what it means by Symmetric(!), and for D, The Median is the middle line in the box plot, which is obviously lower than team b's one.)

6. B (Pretty obvious actually, with the process of elimination. I know it's a bit wordy, but the other statements are basically all saying what's blatantly false, like none of the students liking a temperature of over 65 or under 75, etc.)

swat323 years ago

3 0

B. and D. For the both I'm most likely sure

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(-5/8)×(2/3) what's this answer ?

shutvik [7]

Answer:

Q = -5/8 * 2/3

Multiply both numbers like your multiplying actual numbers.

<h2><em><u></u></em></h2><h2><em><u>A = -10/24 = -5/12</u></em></h2><h2><em><u>Hope this helps</u></em></h2>

6 0

3 years ago

The cost C (in dollars) of making n watches is represented by C = 15n + 85 .

AURORKA [14]

So the answer should be 48.58 if not then it could be 278n

5 0

3 years ago

Which of the following is the weight of the cargo in a truck if 1/3 of the weight is 516 Ibs?

Anni [7]

Answer:

1548 lb

Step-by-step explanation:

Let the truck's weight be w.

Then (1/3)w = 516 lb

Solve for the truck's weight by multiplying both sides of this equation by 3:

w = 1548 lb (Answer B)

8 0

3 years ago

Sylvia took three times in a video game she scored -120 points during her first turn 320 points in her second time and -80 point

sp2606 [1]

Her average score for the 3 turns is 40 because you have to add all of the scores so -80 and -120 is -200 so add that to 320 and you get 120 divide that by 3 because she took 3 turns and you get 40

3 0

3 years ago

A random sample of size n1= 25, taken from a normal population with a standard deviation σ1= 5, has a mean X1= 80. A second rand

sesenic [268]

Answer:

The 94% confidence interval would be given by $2.898 \leq \mu_1 -\mu_2 \leq 7.102$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_1 =80$ represent the sample mean 1

$\bar X_2 =75$ represent the sample mean 2

n1=25 represent the sample 1 size

n2=36 represent the sample 2 size

$\sigma_1 =5$ sample standard deviation for sample 1

$\sigma_2 =3$ sample standard deviation for sample 2

$\mu_1 -\mu_2$ parameter of interest.

The confidence interval for the difference of means is given by the following formula:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2}\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2}}$ (1)

The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =80-75=5$

Since the Confidence is 0.94 or 94%, the value of $\alpha=0.06$ and $\alpha/2 =0.03$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.03,0,1)".And we see that $z_{\alpha/2}=1.88$