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koban [17]
3 years ago
6

1. According to Newton's Second Law of Motion, a net force of an object will cause it to accelerate. How does the Newton's law r

elate to the force of gravity?
2. How does the force of gravity affect the rate of acceleration?
THANKS
Physics
1 answer:
Galina-37 [17]3 years ago
5 0
The gravitational field strength creates forces on mass by pulling it towards the centre the equation is weight=mass*gravitational field strength
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It turns out that Mercury and Mars have the same gravity as one another – that is, you would weigh the same on the surface of Me
Tamiku [17]

Answer:

Explanation:

The value of acceleration due to gravity of mars is same as that the value of acceleration due to gravity of Mercury.

The value of acceleration due to gravity of a planet depends on its mass and the radius.

The formula for the acceleration due to gravity is given by

g=\frac{GM}{R^{2}}

Where, M be the mass of the planet, R be the radius of the planet.

As according to the question, the value of acceleration due to gravity for Mercury is same as that of Mars.

\frac{GM_{mercury}}{R_{mercury}^{2}}=\frac{GM_{mars}}{R_{mars}^{2}}

\frac{M_{mercury}}{R_{mercury}^{2}}=\frac{M_{mars}}{R_{mars}^{2}}

As teh radius of Mercury is small, and acceleration due to gravity is same, it is possible because the mass of Mercury is more than the mass of Mars.

4 0
3 years ago
A body moves on a coordinate line such that it has a position sequals​f(t)equalstsquaredminus4tplus3on the interval 0less than o
Zanzabum

Answer:

A)  Δf = - 49 m, B)  v (7)  = -56 m / s, a = - 8 m / s², C)  t = 0.866 s

Explanation:

A) In this exercise ask to find the displacement and the average velocity, give the function of the movement

           f (t) = - 4t² +3

and the range of motion 0≤ t ≤ 7

the displacement is

for t = 0

           f (0) = 3

for t = 7 s

           f (7) = - 4 7² +3

           f (7) = -46 m

the total displacement is

           Δf = f (7) - f (0)

           Δf = -46 - 3

            Δf = - 49 m

the average speed is defined as the displacement between the time interval

           v = Df / Dt

           v = -49 / 7

           v = - 7 m / s

B) the speed and acceleration of the end points of the motion

         

the speed of defined by

          v = \frac{dx}{dt}

in this case

         v = \frac{df}{dt}

         v = -8t

         

let's calculate

          v (7) = -8 7

          v (7)  = -56 m / s

acceleration is defined by

          a = \frac{dv}{dt}

          a = - 8 m / s²

acceleration is constant throughout the movement

C) the point where the direction changes.

This point is a point where the position goes from positive to negative, the point f = 0

        0 = -4t² +3

        t = √¾

        t = 0.866 s

3 0
3 years ago
A piece of silver metal has a mass of 3.687 grams. If the density of silver is 10.5 g/cm, what is the volume of the silver?​
Aloiza [94]

density =  \frac{mass}{volume}

10.5 = 3.687/volume

volume = 3.687/10.5

volume= 0.3511cm^3

5 0
3 years ago
Describe one piece of evidence to show light waves do not need a medium travel from one place to another
Art [367]

Answer:

I don't know I'm sorry I will tell you another answer asks me

5 0
3 years ago
A ball has m=10 kg and v=10 m/s. It has the same momentum as which of the following?
crimeas [40]

Answer:

Choice d. All three balls listed in choice a, b, and c have a momentum of 100\; \rm kg \cdot m \cdot s^{-1} each, same as that of the 10\; \rm kg ball moving at 10\; \rm m \cdot s^{-1}. Assumption: all four balls are moving in the same direction.

Explanation:

The momentum p of an object is equal to the product of its mass m and its velocity v.

Momentum of a 10\; \rm kg ball moving at 10\; \rm m \cdot s^{-1}:

p = m \cdot v = 10\; \rm kg \times 10\; \rm m \cdot s^{-1} = 100\; \rm kg \cdot m \cdot s^{-1}.

Similarly:

  • Momentum of the ball in choice a: 100 \; \rm kg \times 1\; \rm m \cdot s^{-1} = 100\; \rm kg \cdot m\cdot s^{-1}.
  • Momentum of the ball in choice b: 5 \; \rm kg \times 20\; \rm m \cdot s^{-1} = 100\; \rm kg \cdot m\cdot s^{-1}.
  • Momentum of the ball in choice c: 2 \; \rm kg \times 50\; \rm m \cdot s^{-1} = 100\; \rm kg \cdot m\cdot s^{-1}.

Hence the conclusion that these balls have the same momentum.

7 0
3 years ago
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