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GuDViN [60]
3 years ago
11

An underwater diver sees the sun 50° above horizontal. how high is the sun above the horizon to a fisherman in a boat above the

diver?
Physics
1 answer:
Usimov [2.4K]3 years ago
3 0
Snell's law states that:

n1 Sin∅1 = n2 Sin ∅2

Where, medium 1 with (n1 = 1.33) is water and medium 2 with (n2 = 1) is the air, ∅1 = 90-50 = 40°

Therefore,
Sin ∅2 = n1/n2 *Sin ∅1 = 1.33/1 *Sin 40 = 0.4833=> ∅1 = Sin ^- (0.4833) = 28.9 °

The fisherman the sun at 61.1° (90-∅2) above the horizontal.
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b. A force 100N makes an angle of Ø with the x axis and has a y component of 30 N. Find both the x and y component of the force
horsena [70]

Answer:

Explanation:

The y component of the force is 100 sinØ . But given that y component is 30N

so 100 sinØ = 30

sinØ = 0.3

Ø = 17.5°.

X component of force = 100 cosØ

= 100 cos17.5

= 95.35 N .

Y component of force = 30 N .

Angle Ø = 17.5°.

6 0
3 years ago
What is the method of heat transfer sunlight melts a wax crayon left outside.
Mars2501 [29]

Answer:

Hey Friend....

Explanation:

This is ur answer....

<h3><em>Transfer of energy by electromagnetic waves. Radiation doesn't require matter. Sunlight melting a wax crayon left outside is radiation.</em></h3><h3><em /></h3>

Hope it helps!

Brainliest pls!

Follow me! :)

5 0
2 years ago
A 1300-N crate rests on the floor. How much work is required to move it at constant speed (a)
kherson [118]

a) The work done is 920 J

b) The work done is 5200 J

Explanation:

a)

In this first part of the problem, the crate is moved horizontally at constant speed.

The work required in this case is given by

W=Fd cos \theta

where

F is the magnitude of the force applied

d is the displacement of the crate

\theta is the angle between the direction of the force and of the displacement

Here the crate is moved at constant speed: this means that the acceleration of the crate is zero, and so according to Newton's second law, the net force on the crate is zero: this means that the force applied, F, must be equal to the force of friction (but in opposite direction), so

F = 230 N

The displacement is

d = 4.0 m

And the angle is \theta=0^{\circ}, since the force is applied horizontally. Therefore, the work done is

W=(230)(4.0)(cos 0^{\circ})=920 J

b)

In this case, the crate is moved vertically. The force that must be applied to lift the crate must be equal to the weight of the crate (in order to move it a constant speed), therefore

F = W = 1300 N

The displacement this time is again

d = 4.0 m

And the angle is \theta=0^{\circ}, since the force is applied vertically, and the crate is moved also vertically. Therefore, the work done on the crate this time is

W=(1300)(4.0)(cos 0^{\circ})=5200 J

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

4 0
3 years ago
are the properties of a specific element the same as the properties of a molecule made up of that element ? why or why not
konstantin123 [22]
Because it’s science
8 0
3 years ago
The distance of Saturn from the sun is:<br><br> &lt; 1 A.U.<br> &gt; 1 A.U.<br> = 1 A.U.
sertanlavr [38]

Answer:

1 astronomical unit is the average distance from the Earth to the Sun; approximately 150 million km. At its closest point, Saturn is 9 AU, and then at its most distant point, it's 10.1 AU. Saturn's average distance from the Sun is 9.6 AU. We have written many articles about Saturn for Universe Today.

Explanation:

6 0
3 years ago
Read 2 more answers
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