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yawa3891 [41]
3 years ago
12

You are going sledding with your little cousins during a well-earned break. You push your 23 kg cousin so that they have a speed

of 6 m/s at the top of the hill that is 17 m tall. What is the kinetic energy of your cousin at the top of the hill (after you push)? (in J)
Physics
2 answers:
pogonyaev3 years ago
7 0

Answer:

kinetic energy = 414 J

Explanation:

given data

mass = 23 kg  

speed = 6 m/s  

height = 17 m    

to find out

kinetic energy

solution

we get kinetic energy that is express as

kinetic energy = 0.5 × m × v²    ..........................1

here m is mass and v is speed so

put here value we get kinetic energy

kinetic energy = 0.5 × 23 × 6²

kinetic energy = 414 J

Thepotemich [5.8K]3 years ago
5 0

Answer:

414 J

Explanation:

mass, m = 23 kg

velocity, v = 6 m/s

Kinetic energy is given by

K = 0.5 mv²

K = 0.5 x 23 x 6 x 6

K = 414 J

Thus, the kinetic energy is 414 J.

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lyudmila [28]
Remark
When you are asked a question like this, the first thing to do is search out a formula and put some limits on it.

Formula
I = E/R which comes from E = IR. To get to the derived formula, divide both sides by R
E/R = I*R/R
E/R = I

Discussion
This is an inverse relationship. That means that as one goes up the other one will go down. 

So in this case you keep E constant and you manipulate R and look at your results for I

Case 1

Let us say that E = 10 volts
Let us also say the R = 10 ohms

I = E/R
I = 10/10
I = 1 ohm

Case Two
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Conclusion
As the Resistance goes up, the current goes down. Answer: A
8 0
3 years ago
Read 2 more answers
The label has been scratched off a tuning fork and you need to know its frequency. From its size, you suspect that it is somewhe
bonufazy [111]

Answer:

255 Hz

Explanation:

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With 15 beats per second with the 270 Hz fork, we know the unknown fork is either 270 - 15 = 255Hz or 270 + 15 = 285 Hz (most people would have a hard time discerning 15 beats per second... 5 per second is hard enough)

As 255 is the common frequency, it is the one selected.

3 0
3 years ago
A car slows from 27 m/s to 5 m/s with a constant acceleration for 6.87 s. What is the car’s acceleration?
Kobotan [32]

In this case, the movement is uniformly delayed (the final rapidity is less than the initial rapidity), therefore, the value of the acceleration will be negative.

1. The following equation is used:

a = (Vf-Vo)/ t

a: acceleration (m/s2)

Vf: final rapidity (m/s)

Vo: initial rapidity (m/s)

t: time (s)

2. Substituting the values in the equation:

a = (5 m/s- 27 m/s)/6.87 s

3. The car's acceleration is:

a= -3.20 m/ s<span>^2</span>

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3 years ago
Megan was doing time trials on her bike around a 400m horizontal track. She took 32 seconds to travel 400m. What was her average
Mars2501 [29]
To find average speed, we divide the distance of travel (in this case, 400 metres) by the time she took, 32 seconds.  Therefore: 12.5 seconds is her average speed.
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3 years ago
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if a 0.040-kg stone is whirled horizontally on the end of a 60-m string at a speed of 4.4 m/s, what is the centripetal force ? *
SSSSS [86.1K]

Answer:

0.013N

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F=\frac{mv^{2} }{r}

m=0.04, v=4.4m/s, r=60

F=0.013 N

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