Answer:
v₀ₓ = 28.6 m / s
Explanation:
This is a missile throwing exercise
y = t - ½ g t²
as the dart is thrown horizontally the vertical velocity is zero (I go = 0)
y = - ½ g t²
t =
let's calculate
t =
t = 0.175 s
the expression for horizontal displacement is
x = v₀ₓ t
v₀ₓ = x / t
v₀ₓ = 5.00 / 0.175
v₀ₓ = 28.6 m / s
Answer:
This ball will attain the same range at 60°.
Explanation:
Projectile motion: when an object is thrown in such a way that it form an angle with horizon, the force act on it that is the acceleration due gravity. This type of motion is known as projectile motion.
Range: The horizontal distance is covered by an object.
Range
u = initial velocity = 40 m/s
θ = 30°
g = gravity =9.8 m/s²
Next,
Range and u = 40 m/s
This ball will attain the same range at 60°.
Answer:
Total pressure =1.01*10^5 Pa
Explanation:
given data:
atmospheric pressure = 1.013 *10^5 Pa\
height of water column = 60 cm
Total pressure will be sum of atmospheric pressure and pressure due to water column
P = Atmospheric pressure + pressure due to water column
pressure due to water =
\rho of water = 1420 kg/m^{3}
height of water column = 60 cm =0.60 m
Total pressure = 109649.6 Pa = 1.10*10^5 Pa
Total pressure =1.01*10^5 Pa