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3 years ago

M to the power of 5 n to the power of 3 divided by m to the power of 2 n to the power of -4

Mathematics

1 answer:

neonofarm [45]3 years ago

7 0

When you divide exponents, you subtract the powers.
m^5/m^2 = m^3
n^3/n^-4 = n^7

Answer is (m^3)(n^7)

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the half-life of a new experimental drug in your bloodstream is 15 hours how long will it take for the drug to Decay to 60% of t

Ierofanga [76]

4 hours? i may be wrong

i did - 60 * 15

seems about right, since 50% would be 7.5 hours?

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3 years ago

Write an equation perpendicular to y=-1/5x+9 that passes trough the point (-2,-2)

kow [346]

Answer:

Y=5x + 8

Step-by-step explanation:

The slope of a perpendicular like would be 5

y = 5x + B

-2 = 5(-2)+ B

-2 = -10 + b

b = 8

Y=5x + 8

8 0

3 years ago

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Sam is proving the product property of logarithms.

Charra [1.4K]

Answer: c

Step-by-step explanation: edge 2021

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3 years ago

The ven diagram below is used for showing odd numbers and prime numbers place the numbers 1,2,3,4 and 5 in the ven diagram

kramer

It is right I made this in venn diagram . sorry for poor picture quality

8 0

3 years ago

Use the Midpoint Rule with n = 5 to estimate the volume V obtained by rotating about the y-axis the region under the curve y = 1

velikii [3]

Using the shell method, the volume is given exactly by the definite integral,

$2\pi\displaystyle\int_0^1x(1+9x^3)\,\mathrm dx$

Splitting up the interval [0, 1] into 5 subintervals gives the partition,

[0, 1/5], [1/5, 2/5], [2/5, 3/5], [3/5, 4/5], [4/5, 5]

with left and right endpoints, respectively, for the $i$ -th subinterval

$\ell_i=\dfrac{i-1}5$

$r_i=\dfrac i5$

where $1\le i\le5$ . The midpoint of each subinterval is

$m_i=\dfrac{\ell_i+r_i}2=\dfrac{2i-1}{10}$

Then the Riemann sum approximating the integral above is

$2\pi\displaystyle\sum_{i=1}^5m_i(1+9{m_i}^3)\frac{1-0}5$

$\dfrac{2\pi}5\displaystyle\sum_{i=1}^5\left(\frac{2i-1}{10}+9\left(\frac{2i-1}{10}\right)^4\right)$

$\dfrac{2\pi}{5\cdot10^4}\displaystyle\sum_{i=1}^5\left(16i^4-32i^3+24i^2+1992i-999\right)=\frac{112,021\pi}{25,000}\approx\boxed{14.08}$

(compare to the actual value of the integral of about 14.45)

3 0

3 years ago