Answer: D
Step-by-step explanation:
Consider the first equation. Subtract 3x from both sides.
y−3x=−2
Consider the second equation. Subtract x from both sides.
y−2−x=0
Add 2 to both sides. Anything plus zero gives itself.
y−x=2
To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.
y−3x=−2,y−x=2
Choose one of the equations and solve it for y by isolating y on the left hand side of the equal sign.
y−3x=−2
Add 3x to both sides of the equation.
y=3x−2
Substitute 3x−2 for y in the other equation, y−x=2.
3x−2−x=2
Add 3x to −x.
2x−2=2
Add 2 to both sides of the equation.
2x=4
Divide both sides by 2.
x=2
Substitute 2 for x in y=3x−2. Because the resulting equation contains only one variable, you can solve for y directly.
y=3×2−2
Multiply 3 times 2.
y=6−2
Add −2 to 6.
y=4
The system is now solved.
y=4,x=2
Answer:
x<5
Step-by-step explanation:
the greater sign will firstly be changed to = for better solving so we obtain
3+9x=4(x+7)by opening bracket
3+9x=4x+28
9x-4x=28-3
5x=25
divide all through by 5x
we obtain
x=5
the greater sign change here
which is x<5
Answer:
(4, 9) and (-10, -8)
Step-by-step explanation:
Answer:
30:16-15:8 That is simplified and I divided it by two.
Recall that parallel lines have the same slope.
A line parallel to y= (-3/5)x + 8 would have the same equation EXCEPT for a different constant, C, replacing that '8.'
This new line passes thru (-5,-3). In y= (-3/5)x + C, replace x with -5 and replace y with -3. Then:
-3 = (-3/5)(-5) + C. Find C:
-3 = 3 + C. Thus, C = 6
Thus, the equation of the new line is y= -(3/5)x - 6
Check: Let x = -5 and y = -3. Is the above equation true?
-3 = (-3/5)(-5) - 6
-3 = 3 - 6, or -3 = -3.
