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GenaCL600 [577]
4 years ago
13

Factor: 3x^2+14x-5 (show work)​

Mathematics
1 answer:
stiks02 [169]4 years ago
4 0
After factoring you will get (x+5)(3x-1)
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My friend sets out walking at a speed of 3 miles per hour. I set out behind her 5 minutes later at 4 miles per hour.
MissTica
3 m/h=0.05m/m
.05•5=0.25 m/h I believe?
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3 years ago
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Marizza181 [45]

Answer:

i believe 48 is 5

Step-by-step explanation:

6 0
3 years ago
Problem 10: A tank initially contains a solution of 10 pounds of salt in 60 gallons of water. Water with 1/2 pound of salt per g
AysviL [449]

Answer:

The quantity of salt at time t is m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} }), where t is measured in minutes.

Step-by-step explanation:

The law of mass conservation for control volume indicates that:

\dot m_{in} - \dot m_{out} = \left(\frac{dm}{dt} \right)_{CV}

Where mass flow is the product of salt concentration and water volume flow.

The model of the tank according to the statement is:

(0.5\,\frac{pd}{gal} )\cdot \left(6\,\frac{gal}{min} \right) - c\cdot \left(6\,\frac{gal}{min} \right) = V\cdot \frac{dc}{dt}

Where:

c - The salt concentration in the tank, as well at the exit of the tank, measured in \frac{pd}{gal}.

\frac{dc}{dt} - Concentration rate of change in the tank, measured in \frac{pd}{min}.

V - Volume of the tank, measured in gallons.

The following first-order linear non-homogeneous differential equation is found:

V \cdot \frac{dc}{dt} + 6\cdot c = 3

60\cdot \frac{dc}{dt}  + 6\cdot c = 3

\frac{dc}{dt} + \frac{1}{10}\cdot c = 3

This equation is solved as follows:

e^{\frac{t}{10} }\cdot \left(\frac{dc}{dt} +\frac{1}{10} \cdot c \right) = 3 \cdot e^{\frac{t}{10} }

\frac{d}{dt}\left(e^{\frac{t}{10}}\cdot c\right) = 3\cdot e^{\frac{t}{10} }

e^{\frac{t}{10} }\cdot c = 3 \cdot \int {e^{\frac{t}{10} }} \, dt

e^{\frac{t}{10} }\cdot c = 30\cdot e^{\frac{t}{10} } + C

c = 30 + C\cdot e^{-\frac{t}{10} }

The initial concentration in the tank is:

c_{o} = \frac{10\,pd}{60\,gal}

c_{o} = 0.167\,\frac{pd}{gal}

Now, the integration constant is:

0.167 = 30 + C

C = -29.833

The solution of the differential equation is:

c(t) = 30 - 29.833\cdot e^{-\frac{t}{10} }

Now, the quantity of salt at time t is:

m_{salt} = V_{tank}\cdot c(t)

m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} })

Where t is measured in minutes.

7 0
3 years ago
Perform the indicated operation. 61/2 · 4/5? a.5 1/5 b.6 2/5 c.3 1/5 d.4 2/5
dexar [7]

Answer:

5  1/5

Step-by-step explanation:

6 1/2 *4/5

Rewriting as an improper fraction

( 2*6 +1)/2 *4/5

13/2 *4/5

52/ 10

50/10 + 2/10

5 +1/5

5  1/5

5 0
3 years ago
Read 2 more answers
6(3−y) simplified plz help meeeeeee
Anuta_ua [19.1K]

Answer:

18 - 6y

Step-by-step explanation:

6(3 - y) ← multiply each term in the parenthesis by 6

= 18 - 6y

7 0
3 years ago
Read 2 more answers
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