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2 years ago

What is the value of the expression 6 + 4(8-5)

2 answers:

8 0

6+4(8−5) <---given
6+(4)(3) <--8-5=3
6+12 <---4 x 3=12
18 <--6+12=18
Final answer: 18

matrenka [14]2 years ago

6 0

6+4 (8-5) 6+4 (3) 6+12 =18

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$\boxed{d=v \times t}$
d stands for distance, v stands for speed, t stands for time

The car
d = 48 × t
d = 48t

The motorcycle
d = 20 × t
d = 20t

At the end of t hours, the car is 48t miles (east) from the start point and the motorcycle is 20t miles (north) from the start point.

Second, determine the distance between 48t miles at east and 20t miles at north using pythagoras
distance = $\sqrt{(48t)^{2}+(20t)^{2}}$
distance = $\sqrt{2304t^{2}+400t^{2}}$
distance = $\sqrt{2704t^{2}}$
distance = 52t

The expression for their distance apart at the end of t hours is 52t

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Use the equation I/PT = R I is the interest P is the money before investment and T is the time

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2 years ago

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HELP! WILL GIVE BRAINLIEST!! EASY! GIVE LONG DETAILED ANSWER!

OLEGan [10]

Answer:

x² + 2x + y² + 4y = 20

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Therefore, the center is (-2, -4) and the radius is √25 = 5.

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Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal

lisabon 2012 [21]

Given the following functions below,

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}$

Factorising the denominators of both functions,

Factorising the denominator of f(x),

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}$

Factorising the denominator of g(x),

$\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}$

Multiplying both functions,

$undefined$

4 0

10 months ago