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hodyreva [135]
3 years ago
11

What is the sum of forty-six and ninety-four?

Mathematics
2 answers:
lbvjy [14]3 years ago
8 0

Answer:

140

Step-by-step explanation:

46+94 = 140

vlabodo [156]3 years ago
4 0

Answer:

140

Step-by-step explanation:

46+94=140

Hope it Helps!!

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What is the basic ratio for 25:40
Rashid [163]

The basic ratio of 25:40 would be 5:8.

Since 25:40 is equivalent to the fraction 25/40, you would simplify.


25 (divided by) 5 = 5 


40 (divided by) 5 = 8 


So, the answer is 5:8.

6 0
3 years ago
How do you write 9.009 as a percentage?
Oksanka [162]
900.9% would be 9.009 as a percentage.

It's 900% because it's a whole number and it's .9% because of the last 9 in the number (the thousandth - 3 digits after the decimal).
6 0
3 years ago
. You are working in the advertising department of a company and comparing costs for advertising a new product. Which of these i
VikaD [51]

Answer:

It is 18,307

Step-by-step explanation:

3 0
2 years ago
I need help with this can you explain how to do this so I can understand please ASAP!!
Ratling [72]

Answer: 1.64     2.100

Step-by-step explanation:

The reason for this is squaring something is simply mulyiplying the number by itself. for example

8 squared

there is a 2 above the 8 which means we will do 8x8.

8x8= 64

Hope this helps!!!!

7 0
3 years ago
If the initial velocity stays the same, but the height the projectile is launched from changes , how would the amount of time ch
pickupchik [31]

Answer:

Part A

The height to which the projectile reaches is given by the following formula;

\Delta y = y-y_0 = v_{0y} \times t-\dfrac{1}{2} \times g \times t^2

Where;

v_{0y} = The initial velocity of the projectile = Stays the same

y = The height the projectile reaches

y₀ = The height from which the projectile is launched

g = The acceleration due to gravity

t = The time taken

Given that the projectile has the same initial velocity, the variation of Δy with time, 't', will be the same when the project is launched from a different height, and the time change that it takes for the projectile to reach the maximum height will be the same for the previous launch height

Part B

From the change in eight of the projectile, Δy = y - y₀, the maximum height reached, 'y', is therefore given as follows;

y = Δy + y₀

The maximum height will increase by 'y₀', where 'y₀' is the difference between new height and the previous height, y_i

That is, if y₀ > y_i, the maximum height reached increases and if y₀ < y_i, y₀ will be added as y = Δy - y₀ and the maximum height reached decreases

Step-by-step explanation:

6 0
3 years ago
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