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ANTONII [103]
3 years ago
6

Problem ID: PRABDU8Y Find the value of the variable. 7(m +5) = 21 engage

Mathematics
1 answer:
Nitella [24]3 years ago
8 0
Answer: m= -2

7(m+5) = 21

7m + 35 = 21
-35. -35

7m = -14
————-
7. 7

m = -2
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Which of the following numbers is written in scientific notation?
nata0808 [166]

Answer:

i think is b

Step-by-step explanation:

8 0
3 years ago
Maria studied the traffic trends in India. She found that the number of cars on the road increases by 10% each year. If there we
lord [1]

Answer:

b. 8,800,000.

Step-by-step explanation:

In maria study the number of cars on the road increases by 10% each year.

Total number of cars in the first year =80 million cars.

We will add 10% of 80 million to 80 milion to enable us get the number of cars for the second year.

For year 2 we have;

10% of 80,000,000+80,000,000

\frac{10}{100}*80,000,000+80,000,000

8,000,000 + 80,000,000

88,000,000

number of cars in year 2 = 88 million

We will add 10% of 88 million to 88 milion to enable us get the number of cars for the third year.

\frac{10}{100}*88,000,000+88,000,000

8,800,000+88,000,000

96,800,000

the number of cars on the road in year 3 compared to year 2 will just be the increase which is in BOLD. That is 8,800,000

<em>or simply subtract the number of cars in year 2 from that in year 3;</em>

96,800,000-88,000,000 = 8,800,000

8 0
3 years ago
Read 2 more answers
Please help me with the Math. Thx in advance! <br> Number's 8-11. THANK YOU!
Stella [2.4K]
8 :=7
9= 2/3
10=3/20
11=4
8 0
3 years ago
Read 2 more answers
Factor the following:<br><br> 5∙(a+3)^2-(a+3)
Zanzabum

Answer:

(a+3)(5a+14)

Step-by-step explanation:

Factor the polynomial.

(a+3)(5a+14)

3 0
2 years ago
I need answer Immediately pls!!!!!!
Illusion [34]

Given:

Total number of students = 27

Students who play basketball = 7

Student who play baseball = 18

Students who play neither sports = 7

To find:

The probability the student chosen at randomly from the class plays both basketball and base ball.

Solution:

Let the following events,

A : Student plays basketball

B : Student plays baseball

U : Union set or all students.

Then according to given information,

n(U)=27

n(A)=7

n(B)=18

n(A'\cap B')=7

We know that,

n(A\cup B)=n(U)-n(A'\cap B')

n(A\cup B)=27-7

n(A\cup B)=20

Now,

n(A\cup B)=n(A)+n(B)-n(A\cap B)

20=7+18-n(A\cap B)

n(A\cap B)=7+18-20

n(A\cap B)=25-20

n(A\cap B)=5

It means, the number of students who play both sports is 5.

The probability the student chosen at randomly from the class plays both basketball and base ball is

\text{Probability}=\dfrac{\text{Number of students who play both sports}}{\text{Total number of students}}

\text{Probability}=\dfrac{5}{27}

Therefore, the required probability is \dfrac{5}{27}.

3 0
3 years ago
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