Problem ID: PRABDU8Y Find the value of the variable. 7(m +5) = 21 engage
1 answer:
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Answer:
b. 8,800,000.
Step-by-step explanation:
In maria study the number of cars on the road increases by 10% each year.
Total number of cars in the first year =80 million cars.
We will add 10% of 80 million to 80 milion to enable us get the number of cars for the second year.
For year 2 we have;
10% of 80,000,000+80,000,000
8,000,000 + 80,000,000
88,000,000
number of cars in year 2 = 88 million
We will add 10% of 88 million to 88 milion to enable us get the number of cars for the third year.
8,800,000+88,000,000
96,800,000
the number of cars on the road in year 3 compared to year 2 will just be the increase which is in BOLD. That is 8,800,000
<em>or simply subtract the number of cars in year 2 from that in year 3;</em>
96,800,000-88,000,000 = 8,800,000
Given:
Total number of students = 27
Students who play basketball = 7
Student who play baseball = 18
Students who play neither sports = 7
To find:
The probability the student chosen at randomly from the class plays both basketball and base ball.
Solution:
Let the following events,
A : Student plays basketball
B : Student plays baseball
U : Union set or all students.
Then according to given information,
We know that,
Now,
It means, the number of students who play both sports is 5.
The probability the student chosen at randomly from the class plays both basketball and base ball is
Therefore, the required probability is .