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Lilit [14]
3 years ago
11

How do electric and magnetic forces act on different objects

Physics
1 answer:
GuDViN [60]3 years ago
8 0
They push pull or make object magnetic

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Compare and Contrast electromagnetic waves to infer the relationship between frequency, energy, and wavelength.
natta225 [31]

Answer:

Explanation:This question is simply asking you to describe the following equations:

E = hv

v = c/L

E = hc/L

where E is the energy, h is Planck's constant, v is the frequency, c is the speed of light and L is the wavelength.

By looking at the equations you should be able to tell what the relationships between energy, frequency and wavelength are. If you are having difficulty describing them, then create a table with actual values and see what happens to the energy as you increase or decrease the frequency and/or wavelength.

6 0
2 years ago
A 1/10th scale model of an airplane is tested in a wind tunnel. The reynolds number of the model is the same as that of the full
trasher [3.6K]

Answer:

of the velocity of a full size plane in the air

7 0
4 years ago
50 POINTS!!!!!!!!<br><br> In a GUT (Grand Unified Theory), what is "unified"?
melomori [17]

Subatomic particles

Explanation:

Grand unification theory or GUT is a model that tries to describe the universe.

7 0
3 years ago
3. A 0.98 kg rock is attached to a 0.40-m rope and spun in a vertical
diamong [38]

Answer: v = 6.0 m/s

Explanation:

T = m(v²/R - g)

(T/m + g)R = v²

v = √((79.0/0.98 + 9.81)0.40) = 6.0140... ≈ 6.0 m/s

3 0
3 years ago
A person with normal vision can focus on objects as close as a few centimeters from the eye up to objects infinitely far away. T
NeTakaya

Answer:

a)   f₁ = 3.50 m ,  b)     f₂ = 0.84 m  

Explanation:

For this exercise we must use the constructor equation

          1 / f = 1 / p + 1 / q

where f is the focal length, p is the distance to the object and q is the distance to the image

a) the distance where the image should be placed is q = 3.50 m and the object is located at infinity p = ∞

           1 / f₁ = 1 /∞ + 1 / 3.50

           f₁ = 3.50 m

b) in this case the image is at q = -0.600 m and the object p = 0.350 m

           1 / f₂ = 1 / 0.350 -1 / 0.600

the negative sign, is because the image is in front of the object

           1 / f₂ = 1,1905

            f₂ = 1 / 1,1905

            f₂ = 0.84 m

3 0
4 years ago
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