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3 years ago

_____ is the densest planet. Mercury Venus Earth Mars

Physics

1 answer:

Orlov [11]3 years ago

5 0

The answer is Venus, with the density of 5.204 grams per cubic centimeter

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Suppose an automobile has a kinetic energy of 2800 j. when it moves with six times the speed, what will be its kinetic energy? a

Paladinen [302]

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3 years ago

A 6500 kg satellite orbits a planet. If its distance to the center of the planet is 9e6 m and its speed is 6.7e3 m/s, what is th

Ira Lisetskai [31]

Answer:

the gravitational force between the satellite and the planet is 32.4 * 10³N

Explanation:

It is given that,

Mass of the satellite, m = 6500 kg

Speed of the satellite, v = 6.7 × 10³ m/s

distance to the center of the planet = 9 × 10⁶m

Let F is the magnitude of the gravitational force exerted on the satellite by the planet. The centripetal force is equal to the gravitational force. It is equal to :

$F = \frac{mv^2}{R}$

$F = \frac{6500 \times (6.7 * 10^3)}{9 * 10^6}$

= 32.4 * 10³N

the gravitational force between the satellite and the planet is 32.4 * 10³N

3 0

3 years ago

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A shock wave first forms when an object ___ the speed of sound.

Anna11 [10]

<span>a shock wave first forms when an object Reaches the speed of sound When an object reaches the speed of sound, it will create some sort of disturbance in the air that created discontinuous change in pressure, medium density and the temperature around it, which will eventually became a shock wave.</span><span />

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3 years ago

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PLEASE HELP ASAPPPPP

leva [86]

Answer:

link

Explanation:

ww.comhwhelp

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3 years ago

A hot-air balloon is 11.0 m above the ground and rising at a speed of 7.00 m/s. A ball is thrown horizontally from the balloon b

Nesterboy [21]

Answer:

18.6 m/s

Explanation:

$h$ = Initial height of the balloon = 11 m

$v_{o}$ = initial speed of the ball

$v_{oy}$ = initial vertical speed of the ball = 7 m/s

$v_{ox}$ = initial horizontal speed of the ball = 9 m/s

initial speed of the ball is given as

$v_{o} = \sqrt{v_{ox}^{2} + v_{oy}^{2}} = \sqrt{9^{2} + 7^{2}} = 11.4 m/s$

$v_{f}$ = final speed of the ball as it strikes the ground

$m$ = mass of the ball

Using conservation of energy

Final kinetic energy before striking the ground = Initial potential energy + Initial kinetic energy

$(0.5) m v_{f}^{2} = (0.5) m v_{o}^{2} + mgh \\(0.5) v_{f}^{2} = (0.5) v_{o}^{2} + gh\\(0.5) v_{f}^{2} = (0.5) (11.4)^{2} + (9.8)(11)\\(0.5) v_{f}^{2} = 172.78\\v_{f} = 18.6 m/s$

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3 years ago

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