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stira [4]
3 years ago
13

How many minutes will it take for a car traveling 74 miles per hour to cover 6.50 kilometers?

Chemistry
1 answer:
Dvinal [7]3 years ago
4 0

Answer:

                     3.27 minutes

Explanation:

                    To solve this problem we will first convert miles/hour to km/min. For this purpose we will require following reference conversions as;

                     1 Mile  =  1.60934 Km

And,

                     1 Hour  =  60 min

Therefore,

As,

                     1 Mile  =  1.60934 Km

Then,

                      74 Miles  =  X Km

Solving for X,

                      X  =  74 miles × 1.60934 Km ÷ 1 mile                      

                      X =  119.10 Km

Therefore,

                      119.10 Km were travelled in  =  60 min

So,

                      6.50 Km will be travelled in   =  X min

Solving for X,

                     X  =  60 min × 6.50 Km ÷ 119.10 Km

                     X  =  3.27 minutes

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Answer:

Tetrahedral

Explanation:

For the repulsion of the free electron pair theory, the shape of a molecule will be to repel the bonds and the free electrons on the central atom. In a molecule of carbon tetrachloride, the central atom (C) has no free electrons, so, the shape that repels better the charge is tetrahedral, as shown below.

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Calculate the mass of ethyl alcohol required to prepare 540 grams of C4H6, if the reaction follows the scheme:
kkurt [141]

Answer:

Explanation:

2C₂H₅OH    =   C₄H₆  +  2H₂O  +  H₂

2 mole               1 mole

molecular weight of ethyl alcohol

mol weight of C₂H₅OH = 46 gm            

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540 gm of C₄H₆ = 10 mole

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3 0
3 years ago
identify the part of the slow carbon cycle in whitch the total amount of carbon is most likely decreasing and explain why this d
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Answer:

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2 years ago
BY ANSWERING THIS QUESTION UR PUTTING IT ON UR MOM's LIFE THAT U WON'T STEAL MY POINTS.
Yakvenalex [24]

Answer:

T_2=-125.58\°C

Explanation:

Hello!

In this case, considering the Gay-Lussac's law which describes the pressure-temperature behavior as a directly proportional relationship by holding the volume as constant, we write:

\frac{T_1}{P_1} =\frac{T_2}{P_2}

Whereas solving for the final temperature T2, we get:

T_2=\frac{T_1P_2}{P_1}

Thus, we plug in the given data (temperature in Kelvins) to obtain:

T_2=\frac{(22+273.15)K*1.75atm}{3.50atm} \\\\T_2=147.58K-273.15\\\\T_2=-125.58\°C

Best regards!

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2 years ago
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