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stira [4]
3 years ago
13

How many minutes will it take for a car traveling 74 miles per hour to cover 6.50 kilometers?

Chemistry
1 answer:
Dvinal [7]3 years ago
4 0

Answer:

                     3.27 minutes

Explanation:

                    To solve this problem we will first convert miles/hour to km/min. For this purpose we will require following reference conversions as;

                     1 Mile  =  1.60934 Km

And,

                     1 Hour  =  60 min

Therefore,

As,

                     1 Mile  =  1.60934 Km

Then,

                      74 Miles  =  X Km

Solving for X,

                      X  =  74 miles × 1.60934 Km ÷ 1 mile                      

                      X =  119.10 Km

Therefore,

                      119.10 Km were travelled in  =  60 min

So,

                      6.50 Km will be travelled in   =  X min

Solving for X,

                     X  =  60 min × 6.50 Km ÷ 119.10 Km

                     X  =  3.27 minutes

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If 498 mol of octane combusts, what volume of carbon dioxide is produced at 23.0 °c and 0.995 atm?
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Octane on combustion yields CO₂ and H₂O;

                         2C₈H₁₈<span>  +  2 5O</span>₂    →    16 CO₂<span>  +  18 H</span>₂<span>O
</span>
According to equation,

                      2 moles Octane produces  =  16 moles of CO₂ 
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              498 moles Octane will produce  =  X moles of CO₂

Solving for X,
                                     X  =  (498 mol × 16 mol) ÷ 2 mol

                                     X  =  3984 moles of CO₂

Now,
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As,
                                    P V  =  n R T
Solving for V,
                                        V  =  n R T / P       ------- (1)

Pressure  =  P  =  0.995 atm 
<span>Volume  =  V  =  ? </span>
<span>Moles  =  n  =  3984 </span>
<span>Gas Constant  =  R  =  0.0821 L.atm.K</span>⁻¹.<span>mol</span>⁻¹<span> </span>
<span>Temperature  =  T  =  23 + 273 = 296 K
</span>
Putting values in eq. 1

                V  =  (3984 mol × 0.0821 L.atm.mol⁻¹.K⁻¹ × 296 K) ÷ 0.995 atm

                                      Volume  =  973040.95 L
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