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3 years ago

What is the average Volume of a single penny from the total 25 penny data?

Chemistry

1 answer:

mojhsa [17]3 years ago

7 0

Answer:

1.16 mL

Explanation:

Assume the data show that 25 pennies have a total volume of 29.00 mL.

$\text{Average volume} = \dfrac{\text{29.00 mL}}{25} = \textbf{1.16 mL}$

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Ethyl butyrate, CH3CH2CH2CO2CH2CH3, is an artificial fruit flavor commonly used in the food industry for such flavors as orange

SIZIF [17.4K]

Answer:

A. 10.0 grams of ethyl butyrate would be synthesized.

B. 57.5% was the percent yield.

C. 7.80 grams of ethyl butyrate would be produced from 7.60 g of butanoic acid.

Explanation:

$CH_3CH_2CH_2CO_2H(l)+CH_2CH_3OH(l)+H^+\rightarrow CH_3CH_2CH_2CO_2CH_2CH_3(l)+H_2O(l)$

Moles of butanoic acid = $\frac{7.60 g}{88 g/mol}=0.08636 mol$

According to reaction ,1 mole of butanoic acid gives 1 mol of ethyl butyrate,then 0.08636 mol of butanoic acid will give :

$\frac{1}{1}\times 0.08636 mol=0.08636 mol$ of ethyl butyrate

Mass of 0.08636 moles of ethyl butyrate =

0.08636 mol × 116 g/mol = 10.0 g

Theoretical yield = 10.0 g

Experimental yield = ?

Percentage yield of the reaction = 100%

$Yield\%=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

$100\%=\frac{\text{Experimental yield}}{10.0 g}\times 100$

Experimental yield = 10.0 g

10.0 grams of ethyl butyrate would be synthesized.

Theoretical yield of ethyl butyrate = 10.0 g

Experimental yield ethyl butyrate = 5.75 g

Percentage yield of the reaction = ?

$Yield\%=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

$=\frac{5.75 g}{10.0 g}\times 100=57.5\%$

57.5% was the percent yield.

Moles of butanoic acid = $\frac{7.60 g}{88 g/mol}=0.08636 mol$

According to reaction ,1 mole of butanoic acid gives 1 mol of ethyl butyrate,then 0.08636 mol of butanoic acid will give :

$\frac{1}{1}\times 0.08636 mol=0.08636 mol$ of ethyl butyrate

Mass of 0.08636 moles of ethyl butyrate =

0.08636 mol × 116 g/mol = 10.0 g

Theoretical yield = 10.0 g

Experimental yield = ?

Percentage yield of the reaction = 78.0%

$Yield\%=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

$78.0\%=\frac{\text{Experimental yield}}{10.0 g}\times 100$

Experimental yield = 7.80 g

7.80 grams of ethyl butyrate would be produced from 7.60 g of butanoic acid.

8 0

3 years ago

When scientists first studied electromagnetic energy, many theories were proposed to explain how these waves travel through spac

Aliun [14]

Answer:

Scientists debated the theories with each other and compared the theories with scientific observations

4 0

2 years ago

Read 2 more answers

___MgCl2(s) +___ MiCO3(s)

Doss [256]

Answer:

MgCl2 (s) + Li2CO3 (s) ==> MgCO3 (s) + 2LiCl (aq)

Double Replacement

Explanation:

MgCl2 (s) + Li2CO3 (s) ==> MgCO3 (s) + 2LiCl (aq)

Double Replacement

Halogens are Soluble

Carbonates are Insoluble

This reaction DOES take place.

3 0

2 years ago

Find the number of grams in 16.95 mol hydrogen peroxide (H2O2). Round your

Feliz [49]

Answer: There are 576.46 number of grams present in 16.95 mol hydrogen peroxide $(H_{2}O_{2})$ .

Explanation:

Number of moles is defined as the mass of substance divided by its molar mass.

The molar mass of $H_{2}O_{2}$ is 34.01 g/mol. Hence, mass of hydrogen peroxide present in 16.95 moles is calculated as follows.

$Moles = \frac{mass}{molarmass}\\16.95 mol = \frac{mass}{34.01 g/mol}\\mass = 576.46 g$

Thus, we can conclude that there are 576.46 number of grams present in 16.95 mol hydrogen peroxide $(H_{2}O_{2})$ .

3 0

3 years ago

The Tin Pan Alley era lasted from 1950 to 1967.<br> a. true<br> b. false

fenix001 [56]

I think false is the answer .if wrong correct meeee

7 0

3 years ago