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erma4kov [3.2K]
3 years ago
5

2) What is the concentration of NaCl in a solution prepared by diluting 56.98 ml of 0.5894 M stock

Chemistry
1 answer:
RSB [31]3 years ago
3 0

Answer:

The NaCl concentration will be 0.03 M.

Explanation:

Given data:

Initial volume = V₁ = 56.98 mL (56.98/1000 = 0.05698 L)

Initial concentration = M₁= 0.5894 M

Final volume = V₂= 1.20 L

Final concentration = M₂= ?

Solution:

By diluting the solution volume of solution will increase while number of moles of solute remain the same.

Formula:

Initial concentration × Initial volume  = Final concentration × Final volume

M₁V₁ = M₂V₂

M₂ = M₁V₁ / V₂

M₂ = 0.5894 M × 0.05698 L / 1.20 L

M₂ = 0.0336 M /1.20  

M₂ = 0.03 M

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The molarity of HBr solution is 0.239 M

calculation

write the equation for reaction

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find the moles of LiOH used

moles =molarity x volume

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by use of mole ratio between LiOH :HBr which is 1:1 the moles of HBr is therefore= 5.976 moles

Molarity of HCL= moles /volume

= 5.976/25 = 0.239 M

7 0
3 years ago
The energy produced by the snack in an experiment is calculated to be 41,800 J/g. What is the energy of the snack in Calories/
Goryan [66]

The energy of the snack in calories per gram is 9983.3 Calories/gram.

<h3>What is the energy of a snack?</h3>

The energy that is contained in a snack is obtained from a calorimeter when the snack is burnt in a calorimeter. The mass of the snack that is burnt is measured in terms of energy output of the calorimeter.

If  1 calorie = 4.18J

x calorie = 41,800 J

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x = 9983.3 Calories/gram

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5 0
2 years ago
The element magnesium has significantly fewer protons and neutrons than gold. If you were to use MgMg in place of AuAu in the Ru
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Answer:The center will be quite smaller in magnesium than in gold thus the alpha particle will scatter to a lesser degree and the experiment may not yield a meaningful result.

Explanation:

Gold has seventy nine protons and magnesium has only twelve protons. Gold atoms are quite much more massive than magnesium atoms. This implies that if magnesium atoms were used in Rutherford's experiment, the number of protons will be too few to give a reasonable result since the atom is quite small. A larger atom, having a larger centre is required in order to have meaningful scattering of alpha particles.

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3 years ago
a solution contains 3.00mol of Potassium bromide in 10.0 mol of water. What is the mole fraction of potassium bromide​
stiks02 [169]

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Explanation:

We define mole fraction of a specific compound in a mixture as:

mole fraction of a compound = number of moles of the compound / total number of moles

in our case we have:

number of moles of potassium bromide = 3 moles

total number of moles = number of moles of potassium bromide + number of moles of water

total number of moles = 3 + 10 = 13 moles

mole fraction of potassium bromide = 3 / 13 = 0.23

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3 years ago
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