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Lisa [10]
3 years ago
7

What is the volume of 0.150 M sodium hydroxide, required to react completely with 250.0 mL of 0.545 M acetic acid, CH3COOH solut

ion?
Chemistry
1 answer:
katrin [286]3 years ago
7 0

Answer:

68.81ml

Explanation:

Using the formula:

CaVa = CbVb

Where;

Ca = concentration of acid (M)

Cb = concentration of base (M)

Va = volume of acid (ml)

Vb = volume of base (ml)

Based on the information given in this question;

Ca = 0.545M

Cb = 0.150M

Va = 250ml

Vb = ?

Using CaVa = CbVb

0.545/250 = 0.150/Vb

Cross multiply

250 × 0.150 = 0.545Vb

37.5 = 0.545Vb

Vb = 37.5/0.545

Vb = 68.81ml

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Calculating enthalpy of formation of this reaction from the standard heats of formation of the products and reactants:

ΔH_{reaction}^{0}=[H_{f}^{0}(Al_{2}O_{3}(s)) + (3*H_{f}^{0}(H_{2}SO_{4}(aq))] -   [H_{f}^{0}(Al_{2}SO_{4}(aq)) + (3*H_{f}^{0}(H_{2}O(l))]

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Total enthalpy change when 15 mol of Al_{2}(SO_{4})_{3}reacts will be=

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