What is the volume of 0.150 M sodium hydroxide, required to react completely with 250.0 mL of 0.545 M acetic acid, CH3COOH solut
ion?
1 answer:
Answer:
68.81ml
Explanation:
Using the formula:
CaVa = CbVb
Where;
Ca = concentration of acid (M)
Cb = concentration of base (M)
Va = volume of acid (ml)
Vb = volume of base (ml)
Based on the information given in this question;
Ca = 0.545M
Cb = 0.150M
Va = 250ml
Vb = ?
Using CaVa = CbVb
0.545/250 = 0.150/Vb
Cross multiply
250 × 0.150 = 0.545Vb
37.5 = 0.545Vb
Vb = 37.5/0.545
Vb = 68.81ml
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