The equilibrium solubility of cadmium carbonate in a solution at constant pH of 11 is 1.65 x 10⁻⁵ mol/dm³.
<h3>Equilibrium solubility of the compound</h3>
The equilibrium solubility of cadmium carbonate in a solution at constant pH of 11 is calculated as follows;
H₂CO3 ⇄ 2H⁺ + CO₃²⁻
x : 2x x
ksp = (2x)²x
ksp = 4x³
(1.8 x 10⁻¹⁴) = 4x³
(1.8 x 10⁻¹⁴) /4 = x³
4.5 x 10⁻¹⁵ = x³
x = (4.5 x 10⁻¹⁵)^¹/₃
x = 1.65 x 10⁻⁵ mol/dm³
Thus, the equilibrium solubility of cadmium carbonate in a solution at constant pH of 11 is 1.65 x 10⁻⁵ mol/dm³.
Learn more about equilibrium solubility here: brainly.com/question/23946616
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A molecule is a group a atoms joined together in a particular way.
Answer:
The answer to your question is: 3000 cm
Explanation:
30 meters long to cm
We can use a rule of three to solve it
We know that 1 meter ------------------ 100 cm
30 meters ---------------- x
x = 30(100)/1 = 3000 cm
Answer:
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