Answer:
The correct answer is 0.089 g/L ≅ 0.09 g/L
Explanation:
Density is defined as: mass/volume.
From the problem we have:
number of moles = n = 3 mol
volume = V = 67.20 L
We have to calculate the mass. For this, we need the molar mass (MM) of the gas. That is easily calculated from the molar mass of the element hydrogen (H), as we know that hydrogen gas has the molecular formula H₂:
MM(H₂) = 2 x molar mass H = 2 x 1 g/mol = 2 g/mol
Now, we multiply n by MM to obtain the mass (m) of the gas:
m = n x MM(H₂) = 3 mol x 2 g/mol = 6 g
Finally, we calculate the density from the mass and volume:
density = m/V = 6 g/(67.20) = 0.089 g/L ≅ 0.09 g/L
Answer:
Kp and Kc are 0.01266 and 145.17, respectively.
Explanation:
Please check document attached.
Recognizing the Structure of the Periodic Table. Read the periodic table from top left to bottom right. The elements are ordered by their atomic numbers, which increase as you move across and down the periodic table. The atomic number is how many protons the element's atom possesses.
Answer:
30.0 L.
Explanation:
- To solve this problem; we must mention the rule states the no. of millimoles of a substance before and after dilution is the same.
<em>(MV)before dilution = (MV)after dilution</em>
M before dilution = 5.0 M, V before dilution = 3.0 L.
M after dilution = 0.5 M, V after dilution = ??? L.
∵ (MV)before dilution = (MV)after dilution
∴ (5.0 M)(3.0 L) = (0.5 M)(V after dilution)
<em>∴ V after dilution = (5.0 M)(3.0 L)/(0.5 M) = 30.0 L.</em>
Answer :
(1) is act as a base and act as an acid.
(2) We can not classified as a base or an acid.
Explanation :
According to Arrhenius concept, a base is defined as a substance which donates hydroxide ions when dissolved in water and an acid is defined as a substance which donates hydronium ions in water.
(1) The given chemical reaction is:
In this reaction, produces ions and produces ions.
Thus, is act as a base and act as an acid.
(2) The given chemical reaction is:
Arrhenius concept is only applicable on aqueous solution. Thus, we can not classified as a base or an acid.