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3 years ago

Approximately how many years does it take for one centimeter of soil to form? *

Chemistry

1 answer:

raketka [301]3 years ago

3 0

Answer:

The time needed to form a soil depends on the latitude: in environments characterized by a mild climate, it takes 200-400 years to form 1 cm of soil. in wet tropical areas soil formation is faster, as it takes 200 years. in order to accumulate enough substances to make a soil fertile it takes 3000 years.

Explanation:

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(01.01 MC)

user100 [1]

The dependent variable is plant height.

The dependent variable (plant height) is the property that changes as a result something the scientist does.

The independent variable is the property that the scientist changes systematically (the amount of CO_2) to see its effect.

The number of plants and the types of plants are uncontrolled variables. They may or may not affect the heights of the plants.

5 0

3 years ago

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Why a plant can survive longer than bacteria

Arlecino [84]

Answer:

Bacteria are vital in keeping nitrogen cycling through the ecosystem, and nitrogen is vital to plant growth. Without bacteria around to break down biological waste, it would build up. And dead organisms wouldn't return their nutrients back to the system

Explanation:

3 0

2 years ago

A student does an experiment to determine the molar solubility of lead(II) bromide. She constructs a voltaic cell at 298 K consi

attashe74 [19]

Answer:

The molar solubility of lead bromide at 298K is 0.010 mol/L.

Explanation:

In order to solve this problem, we need to use the Nernst Equaiton:

$E = E^{o} - \frac{0.0591}{n} log\frac{[ox]}{[red]}$

E is the cell potential at a certain instant, E⁰ is the cell potential, n is the number of electrons involved in the redox reaction, [ox] is the concentration of the oxidated specie and [red] is the concentration of the reduced specie.

At equilibrium, E = 0, therefore:

$E^{o} = \frac{0.0591}{n} log \frac{[ox]}{[red]} \\\\log \frac{[ox]}{[red]} = \frac{nE^{o} }{0.0591} \\\\log[red] = log[ox] - \frac{nE^{o} }{0.0591}\\\\[red] = 10^{ log[ox] - \frac{nE^{o} }{0.0591}} \\\\[red] = 10^{ log0.733 - \frac{2x5.45x10^{-2} }{0.0591}}\\\\$

[red] = 0.010 M

The reduction will happen in the anode, therefore, the concentration of the reduced specie is equivalent to the molar solubility of lead bromide.

7 0

3 years ago

Calculate the change in the kinetic energy (KE) of the bottle when the mass is increased. Use the formula

DerKrebs [107]

Answer:

1 kg

2 kg

3 kg

4 kg

Explanation:

i did the assignment

8 0

3 years ago

For the reaction ? Fe+? H2o ⇀↽? Fe3o4+? H2 , a maximum of how many grams of fe3o4 could be formed from 354 g of fe and 839 g of

Evgesh-ka [11]

The given reaction is:

3Fe + 4H2O → Fe3O4 + 4H2

Given:

Mass of Fe = 354 g

Mass of H2O = 839 g

Calculation:

Step 1 : Find the limiting reagent

Molar mass of Fe = 56 g/mol

Molar mass of H2O = 18 g/mol

# moles of Fe = mass of Fe/molar mass Fe = 354/56 = 6.321 moles

# moles of H2O = mass of h2O/molar mass of H2O = 839/18 = 46.611 moles

Since moles of Fe is less than H2O; Fe is the limiting reagent.

Step 2: Calculate moles of Fe3O4 formed

As per reaction stoichiometry:

3 moles of Fe form 1 mole of Fe3O4

Therefore, 6.321 moles of Fe = 6.321 * 1/ 3 = 2.107 moles of Fe3O4

Step 4: calculate the mass of Fe3O4 formed

Molar mass of Fe3O4 = 232 g/mol

# moles = 2.107 moles

Mass of Fe3O4 = moles * molar mass

= 2.107 moles * 232 g/mol = 488.8 g (489 g approx)

7 0

3 years ago

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