Answer:
A. LiCl
Explanation:
Lithium chloride is an ionic compound but it also has some covalent character due to the very small size of lithium metal.
<span>Ionization energy (IE) is the amount of energy required to remove an electron.
If you observe the IEs sequentially, there is a large gap between the 2nd and 3rd. This suggests it is difficult to remove more than 2 two electrons. Elements that lose two electrons to become more stable are found in the Group 2A (2 representing the number of electrons in the outermost valence shell).</span>
Answer:
Insulators
Explanation:
Insulators consists of air, water etc.
Answer:
The van't Hoff factor = 3.20
Explanation:
Step 1: data given
Osmotic pressure of a 0.050 M Solution is 3.85 atm
Temperature = 20.0 °C
Step 2:
Osmotic pressure depends on the molar concentration of the solute but not on its identity.
We can calculate the osmotic pressure by:
π = i.M.R.T
⇒ with π = osmotic pressure = 3.85 atm
⇒ with i = van 't Hoff factor = TO BE DETERMINED
⇒ with M = molar concentration of the solution =0.050 M
⇒ with R = gas constant =0.08206 L * atm / mol* K)
⇒ with T = Temperature of the solution =20°C = 293 K
i = π / M.R.T
i = 3.85 / 0.050*0.08206*293
i = 3.20
The theoretical Van't Hoff factor is 4:
AlCl3(aq) → Al^3+(aq) + 3Cl^-(aq)
AlCl3 dissociates in 1 mol Al^3+ + 3 moles Cl-
Due to the interionic atractions the Van't hoff factor is less than the theoretical value of 4
Answer:
D) the carbon with the low-energy phosphate on it in 1,3 BPG is labeled.
Explanation:
Glycolysis has 2 phase (1) preparatory phase (2) pay-off phase.
<u>(1) Preparatory phase</u>
During preparatory phase glucose is converted into fructose-1,6-bisphosphate. Till this time the carbon numbering remains the same i.e. if we will label carbon at 6th position of glucose, its position will remian the same in fructose-1,6-bisphosphate that means the labeled carbon will still remain at 6th position.
When fructose-1,6-bisphosphate is further catalyzed with the help of enzyme aldolase it is cleaved into two 3 carbon intermediates which are glyceraldehyde 3-phosphate (GAP) and dihyroxyacetone phosphate (DHAP). In this conversion, the first three carbons of fructose-1,6-bisphosphate become carbons of DHAP while the last three carbons of fructose-1,6-bisphosphate will become carbons of GAP. It simply means that GAP will acquire the last carbon of fructose-1,6-bisphosphate which is labeled. Now the last carbon of GAP which has phosphate will be labeled.
<u>(2) Pay-off phase</u>
During this phase, GAP is dehydrogenated into 1,3-bisphosphoglycerate (BPG) with the help of enzyme glyceraldehyde 3-phosphate dehydrogenase. This oxidation is coupled to phosphorylation of C1 of GAP and this is the reason why 1,3-bisphosphoglycerate has phosphates at 2 positions i.e. at position 1 in which phosphate is newly added and position 3rd which already had labeled carbon.
It is pertinent to mention here that<u> BPG has a mixed anhydride and the bond at C1 is a very high energy bond.</u> In the next step, this high energy bond is hydrolyzed into a carboxylic acid with the help of enzyme phosphoglycerate kinase and the final product is 3-phosphoglycerate. Hence, the carbon with low energy phosphate i.e. the carbon at 3rd position remains labeled.
