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kati45 [8]
3 years ago
5

Chlorofluorocarbons photodissociate to produce chlorine atoms, cl•, which have been implicated in decreasing the concentration o

f ozone, o3, in the stratosphere. the decomposition of the ozone follows a reaction sequence of o3 cl• -> clo• o2 clo• o -> cl• o2 what role (factor affecting reaction rates) do chlorine atoms have in increasing the depletion rate of ozone
Chemistry
1 answer:
GrogVix [38]3 years ago
8 0

Answer:

The role that chlorine atoms have in increasing the depeltion rate ozone is that Cl acts as a catalyst.

Explanation:

  • From the two steps of the reaction:
  1. O₃ + Cl· → ClO· + O₂
  2. ClO· + O → Cl· + O₂
  • The overall reaction is: O₃ + O → 2O₂
  • It is clear that ClO· is an intermediate that has been produced within the first step and has been consumed in the second step.
  • Also, Cl· is considered as a catalyst in this reaction that it has been consumed in the first step and has been produced in the second step, which means that it does not get up in the reaction, that is the main characteristic of the catalyst.
  • The catalyst usually increases the rate of the reaction by lowering its energy of activation (The minimum energy that is required to initiate the reaction) by proceeding the reaction in an alternative pathway <em>(changing the reaction mechanism)</em>.
  • Hence, the role affecting the reaction rate that chlorine atoms have in increasing the depletion rate of ozone that it acts as a catalyst and does not get used up in the reaction.
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the standard change in Gibbs free energy is Δ????°′=7.53 kJ/molΔG°′=7.53 kJ/mol . Calculate Δ????ΔG for this reaction at 298 K29
Vera_Pavlovna [14]

Answer:

ΔG = 16.218 KJ/mol

Explanation:

  • dihydroxyacetone phosphate ↔ glyceraldehyde-3-phosphate
  • ΔG = ΔG° - RT Ln Q

∴ ΔG° = 7.53 KJ/mol * ( 1000 J / KJ ) = 7530 J/mol

∴  R = 8.314 J/K.mol

∴ T = 298 K

∴ Q = [glyceraldehyde-3-phosphate] / [dihydroxyacetone phosphate]

⇒ Q = 0.00300 / 0.100 = 0.03

⇒ ΔG = 7530J/mol - (( 8.314 J/K.mol) * ( 298 K ) * Ln ( 0.03 ))

⇒ ΔG = 16217.7496 J/mol ( 16.218 KJ/mol )

5 0
4 years ago
Which of the following isoelectronic series is correctly ranked from largest ionic radius to smallest ionic radius? 1. N 3−, O 2
love history [14]

Answer:

<u>Option 1</u>:  N⁻³ > O⁻² > F⁻ > Na⁺ > Mg⁺²    

Explanation:

<u>Ionic radius is the radius of an atom´s ion in ionic crystal structure</u>.<u> </u><u><em>In an ion that lose an electron, to form a cation, the radius of the ion gets smaller</em></u><em>, </em>because the repulsion between electrons decrease because fewer electrons are present. Conversely, <u><em>adding on electron to a neutral atom, to form an anion, causes electron - electron repulsions to increase, so the size of the radius of the ion gets bigger.</em></u>                  

<u><em>Isoelectronic species are ions or elements that have the same number of electrons in their electronic shells but have different overall charges, because of their different atomic numbers</em></u>.                        

<u><em>In a isolelectronic series (same number of electrons),</em></u> <u><em>the increase of the positive charge (given by the number of protons in the nucleus), will cause a decrease in radius </em></u>beacuse the greater electrostatic attraction between the electrons and the nucleus. Consequently, the ion with the greatest nuclear charge will have the smallest ionic radius and the ion with the smallest nulear charge will have the largest ionic radius.  

<u>We will use this principle to solve our problem</u>.  

In our case, the given ions are:  

  • N⁻³ :    Z = 7,  e⁻ = 10
  • O⁻²:     Z= 8,   e⁻ =10
  • F⁻:       Z = 9,  e⁻ = 10
  • Na⁺:    Z= 11,   e⁻ = 10
  • Mg⁺²:  Z=12,   e⁻ =10

where Z= number of protons, and e⁻ = number of electrons.

<em><u>Hence the decreasing order of ionic radius is:</u></em>

N⁻³ > O⁻² > F⁻ > Na⁺ > Mg⁺²  

Have a nice day!

4 0
3 years ago
Not too sure about this one
Kazeer [188]

Answer:

It should be polarity

8 0
3 years ago
Help please
Mars2501 [29]

Answer:

electron cloud charge of manganese=-5

Explanation:

atomic number=number of elecron +neutron number

DATA

Neutron NO.=30

atomic NO.=25

e=?

A=e+n

25=e+30

e=25-30

e= -5

6 0
3 years ago
Calculate 18.9 minus 2.15. Round the answer to the correct number of significant figures.
Lerok [7]
The answer is 16.75 it rounds to 17 Hope this helps! ;D
7 0
3 years ago
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