The volume of ammonia gas is 4096 mL.
Explanation:
As per the kinetic theory of gases, the volume occupied by gas molecules will be directly proportional to the temperature and number of moles of the gas molecules. Similarly, the volume occupied by gas molecules will be inversely proportional to pressure.
PV = nRT
So, V = nRT/P
As R = 0.082 L atm mol⁻¹ K⁻¹ , T = 273 K and P = 1 atm with n = 0.183 mol
Then,
V=(0.183*0.082*273)/1
V = 4.096 L = 4096 mL.
Thus, the volume of ammonia gas is 4096 mL.
For the triplet AUG, I got methionine, which is a start codon. For GCU, I got alanine.
O B. The total mass of the reactants equals the total mass of the
products.
Answer:
The moles of KClO3 = 0.052 moles
Explanation:
Step 1: Calculate the pressure of oxygen gas
The oxygen has a total pressure (including water vapour) of 760 mmHg
The pressure of Oxygen = (760 - 26) mmHg
= 734 mmHg of water vapor
Step 2: Calculate the no of moles of oxygen
Using Ideal gas equation
P V = n R T
P = pressure of oxygen in N/m2 ( you should convert 734 mmHg to pascal or N/m2) = 97,858.6 N/m2 or pas
V = 2 litres = 0.002 m3
R = gas constant = 8.31
T= 27oC = 300 K
Applying this equation P V = n R T
97,858.6 x 0.002 = n x 8.31 x 300
n = 0.0785 mol of Oxygen
From the balanced equation
2 KClO 3 ---- 2 KCl + 3 O 2
3 moles of oxygen is produced from 2 moles KClO3
so 0.0785 mole of oxygen will be produced from x
x = (0.0785 x 2 ) / 3
x = 0.052 moles of KClO3
Answer: negative acellaration or mass.
Explanation:
the first reason why is that i got that quistion right. and when objects are unbalanced it gives negative acellaration