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Kryger [21]
3 years ago
9

Need help really please​

Mathematics
2 answers:
Gre4nikov [31]3 years ago
4 0

Answer:

the decimal is 1.36

the fraction is 34/25

Step-by-step explanation:

so you have on full grid and you have one that has 36 squares filled.

Tatiana [17]3 years ago
4 0

Answer:

I'm pretty sure the decimal would be 1.36. (If it's incorrect feel free to report my answer.)

Step-by-step explanation:

The first square is completely filled, which would be 1. Then it goes by tenths in the next one, only 3 of them are filled so it would be 1.3. Lastly, count the ones place values, the individual ones, which is 6, I believe. (It was very hard to count them with it being so small.)  I hope this helps you! :)

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Determine the kinetic energy of a 100-kg roller coaster car that is moving with a speed of 20.0/ms.
rjkz [21]

Answer:

The kinetic energy is 20,000\ J

Step-by-step explanation:

The kinetic energy of a body is defined as:

k = \frac{1}{2}ms ^ 2

Where <em>m</em> is the mass of the roller coaster car

<em>s</em> is the speed and <em>k</em> is the kinetic energy

We know that s = 20\ m/s

m = 100\ kg

Then the kinetic energy of the roller coaster car is:

k = \frac{1}{2}(100)(20) ^ 2\\\\k = 50(20) ^ 2\\\\k = 50 * 400\\\\k = 20,000\ J

3 0
3 years ago
Enter the data to create a histogram. Then select the correct answer.
Verizon [17]

Answer: The histogram is not symmetrical

5 0
3 years ago
Read 2 more answers
Help please solve<br> <img src="https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B6x%5E5%2B11x%5E4-11x-6%7D%7B%282x%5E2-3x%2B1
Shkiper50 [21]

Answer:

\displaystyle  -\frac{1}{2} \leq x < 1

Step-by-step explanation:

<u>Inequalities</u>

They relate one or more variables with comparison operators other than the equality.

We must find the set of values for x that make the expression stand

\displaystyle \frac{6x^5+11x^4-11x-6}{(2x^2-3x+1)^2} \leq 0

The roots of numerator can be found by trial and error. The only real roots are x=1 and x=-1/2.

The roots of the denominator are easy to find since it's a second-degree polynomial: x=1, x=1/2. Hence, the given expression can be factored as

\displaystyle \frac{(x-1)(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)^2(x-\frac{1}{2})^2} \leq 0

Simplifying by x-1 and taking x=1 out of the possible solutions:

\displaystyle \frac{(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)(x-\frac{1}{2})^2} \leq 0

We need to find the values of x that make the expression less or equal to 0, i.e. negative or zero. The expressions

(6x^3+14x^2+10x+12)

is always positive and doesn't affect the result. It can be neglected. The expression

(x-\frac{1}{2})^2

can be 0 or positive. We exclude the value x=1/2 from the solution and neglect the expression as being always positive. This leads to analyze the remaining expression

\displaystyle \frac{(x+\frac{1}{2})}{(x-1)} \leq 0

For the expression to be negative, both signs must be opposite, that is

(x+\frac{1}{2})\geq 0, (x-1)

Or

(x+\frac{1}{2})\leq 0, (x-1)>0

Note we have excluded x=1 from the solution.

The first inequality gives us the solution

\displaystyle  -\frac{1}{2} \leq x < 1

The second inequality gives no solution because it's impossible to comply with both conditions.

Thus, the solution for the given inequality is

\boxed{\displaystyle  -\frac{1}{2} \leq x < 1 }

7 0
3 years ago
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Katen [24]

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The absolute value of -2 is just 2 so now it is

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4 0
3 years ago
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aleksklad [387]

Answer:

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Step-by-step explanation:

The sides of a rhombus are congruent , thus

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8z = 72 ( divide both sides by 8 )

z = 9

Then

BC = 9z = 9 × 9 = 81

Since the sides are congruent, then DE = 81

6 0
3 years ago
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