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DerKrebs [107]
3 years ago
15

Which water depth had the biggest difference in survival rates for embryos with UV-B protection versus embryos without UV-B prot

ection? Which water depth had the biggest difference in survival rates for embryos with UV-B protection versus embryos without UV-B protection? 100 cm 0 cm 10 cm 50 cm

Physics
1 answer:
sergiy2304 [10]3 years ago
6 0

Answer:

10 cm

Explanation:

water depth had the biggest difference in survival rates for embryos with UV-B protection versus embryos without UV-B protection is 10 cm . the bar graph attached in the shows that the lengths of yellow and brown bars differ the most at 10 cm.

Hence,The biggest difference between the survival rates of UV-B protected and unprotected can be seen at the depth of 10 cm.

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John F. Kennedy was the youngest man ever to be elected President of the United States.
Furkat [3]
False. Theodore Roosevelt was the youngest.
5 0
3 years ago
The net force experienced by an object is increased. What affect does this have on the acceleration of the object?
Evgesh-ka [11]

Answer:

The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased.

Explanation:

hope it helps pls give me brainless

6 0
3 years ago
A kite 100 ft above the ground moves horizontally at a speed of 11 ft/s. At what rate is the angle (in radians) between the stri
frutty [35]

Answer:

-2.26×10^-4 radians

Explanation:

The solution involves a right angle triangle

Length is z while the horizontal is the height x

X^2+ 100^2=z^2

Taking the derivatives

2x(dx/dt)=Z^2(dz/dt)

Specific moments = Z= 200 ,X= 100sqrt3 and dx/dt= 11

dz/dt= 1100sqrt3/200 = 9.53

Sin a= 100/a

Taking derivatives in terms of t

Cos a(da/dt)=100/z^2 dz/dt

a= 30°

Cos (30°)da/dt= (-100/40000×9.5)

a= -2.26×10^-4radians

8 0
3 years ago
Read 2 more answers
If the mass of an object is 8 kg and its momentum is -80 kgm/s, what is its velocity?
Dimas [21]

An object's momentum is the product of its mass and its velocity:

p = mv

p is its momentum, m is its mass, and v is its velocity.

Given values:

p = -80kg×m/s

m = 8kg

Plug in these values and solve for v:

-80 = 8v

v = -10m/s

Choice D

4 0
3 years ago
If there is a huge boulder on your lawn and you want to determine its density, but it is
Olin [163]

There are different options here but all of them work by approximating and assuming.

i) that the boulder is above ground.

ii) that the bottom surface of the boulder is known.

iii) the shape of the boulder is taken into account.

The most accurate way is measuring it by displacement method but the boulder is immovable hence the volume can be calculated by measuring the boulder or a waterproof box to be built around the boulder and calculate the volume occupied by boulder.

All the above methods are estimating methods.

*Another way to find the density is through specific gravity.

S.G = <u>Density</u><u> </u><u>of</u><u> </u><u>object</u>

Density of water

If the material that makes the boulder is known that is if it's stone or a mineral then the specific gravity can be found.

If the boulder is purely rock then S.G lies between 3 - 3.5 and the density of water is known thus the density of the boulder can be found without moving the boulder.

This is what I think after correction and allthe best!

3 0
2 years ago
Read 2 more answers
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