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Svet_ta [14]
3 years ago
11

Which equation represents a circle with a center at (2, –8) and a radius of 11? (x – 8)2 + (y + 2)2 = 11 (x – 2)² + (y + 8)² = 1

21 (x + 2)² + (y – 8)² = 11 (x + 8)² + (y – 2)² = 121
Mathematics
2 answers:
kiruha [24]3 years ago
6 0

Answer:

its B

Step-by-step explanation:

because that is the answer

lawyer [7]3 years ago
4 0

Answer:The answer B: (x – 2)² + (y + 8)² = 121

Step-by-step explanation:

Just took the test on edge

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Find the work done by the force Bold Upper F equals xy Bold i plus (y minus x )Bold j over the straight line from (negative 1 co
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Answer:

<h2>4/3 Joules </h2>

Step-by-step explanation:

Work is said to be done when force applied to an object causes the object to move through a distance.

Work done = Force * perpendicular distance.

\int\limits^a_b {F} \, ds

Given Force F = xy i + (y-x) j and a straight line (-1, -2) to (1, 2)

First we need to get the equation of the straight line given.

Given the slope intercept form y = mx+c

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m = 4/2

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To get the slope we will substtutte any f the point and the slope into the formula y = mx+c

Using the point (1,2)

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W = \int\limits^a_b ({2x^2 i + x j}) \, (i+2j)\\W = \int\limits^a_b ({2x^{2}+2x }) \, dx \\W = [\frac{2x^{3} }{3} +x^{2} ]\left \ x_2=1} \atop {x_1=-1}} \right.\\W = (2(1)^3/3 + 1^2) -  (2(-1)^3/3 + (-1)^2)\\W =(2/3+1) - (-2/3+1)\\W = 2/3+2/3+1-1\\W = 4/3 Joules

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3 years ago
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