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Svet_ta [14]
3 years ago
11

Which equation represents a circle with a center at (2, –8) and a radius of 11? (x – 8)2 + (y + 2)2 = 11 (x – 2)² + (y + 8)² = 1

21 (x + 2)² + (y – 8)² = 11 (x + 8)² + (y – 2)² = 121
Mathematics
2 answers:
kiruha [24]3 years ago
6 0

Answer:

its B

Step-by-step explanation:

because that is the answer

lawyer [7]3 years ago
4 0

Answer:The answer B: (x – 2)² + (y + 8)² = 121

Step-by-step explanation:

Just took the test on edge

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Find two consecutive whole numbers that square root 97 lies between
lora16 [44]

Answer: 9 and 10

Step-by-step explanation:

To understand this question we need to first understand how to solve square root equations! The easiest way to learn how to solve square root problems is by finding the reverse of the problem.

For example, if you tried to find the square root of 25, you would reverse the problem to do 5^2 = 5 x 5 = 25.

So if we were to implement this problem, we would look at these two whole numbers.

9^2 = 9 x 9 = 81

10^2 = 10 x 10 = 100

Thus meaning that the only two numbers that the square root of 97 lies between can be 9 and 10!

It's important to rely on your knowledge of multiplication to develop a strong base for square roots.  

8 0
3 years ago
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$6.62 for 2 pounds of tomatoes? Please explain!
exis [7]

Answer: each tomato is $3.31

Step-by-step explanation:

5 0
2 years ago
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The weekly ad for a local grocery store advertises a 5 pound bag of organic apples for $13.95. Round each rate to the nearest hu
beks73 [17]

Answer:

$2.79 per pound of apples.

0.36 pounds per dollar.

The unit rate representing cost of per pound apples is typically used.

Step-by-step explanation:

We have been given that the weekly ad for a local grocery store advertises a 5 pound bag of organic apples for $13.95.

Since we know when rates are expressed as a quantity of 1, such as 100 meter per second or 5 miles per hour, they are called unit rates. We need to have 1 in our denominator to express two quantities as unit rate.

Let us find the unit rate in terms of cost of per pound bag of apples.

\text{Unit rate as the cost of organic apples per pound}=\frac{\$13.95}{5 \text{ pounds of organic apples}}

\text{Unit rate as the cost of organic apples per pound}=\frac{\$2.79} {\text{ pound of organic apples}}

Therefore, our unit rate will be $2.79 per pound of apples.

Let us find unit rate of pounds of apples per dollar.

\text{Unit rate as the pounds of organic apples per dollar}=\frac{5\text{ pounds of organic apples}}{\$13.95}

\text{Unit rate as the pounds of organic apples per dollar}=\frac{0.3584 \text{ pounds of organic apples}}{\$}

\text{Unit rate as the pounds of organic apples per dollar}\approx \frac{0.36 \text{ pounds of organic apples}}{\$}

Therefore, our another unit rate will be 0.36 pounds per dollar.

Since, we purchase apples or other items according to their price per piece or their price per pound in our daily life, therefore, the unit rate representing cost of per pound apples is typically used.

3 0
3 years ago
Read 2 more answers
The mean number of words per minute (WPM) read by sixth graders is 8888 with a standard deviation of 1414 WPM. If 137137 sixth g
Bingel [31]

Noticing that there is a pattern of repetition in the question (the numbers are repeated twice), we are assuming that the mean number of words per minute is 88, the standard deviation is of 14 WPM, as well as the number of sixth graders is 137, and that there is a need to estimate the probability that the sample mean would be greater than 89.87.

Answer:

"The probability that the sample mean would be greater than 89.87 WPM" is about \\ P(z>1.56) = 0.0594.

Step-by-step explanation:

This is a problem of the <em>distribution of sample means</em>. Roughly speaking, we have the probability distribution of samples obtained from the same population. Each sample mean is an estimation of the population mean, and we know that this distribution behaves <em>normally</em> for samples sizes equal or greater than 30 \\ n \geq 30. Mathematically

\\ \overline{X} \sim N(\mu, \frac{\sigma}{\sqrt{n}}) [1]

In words, the latter distribution has a mean that equals the population mean, and a standard deviation that also equals the population standard deviation divided by the square root of the sample size.

Moreover, we know that the variable Z follows a <em>normal standard distribution</em>, i.e., a normal distribution that has a population mean \\ \mu = 0 and a population standard deviation \\ \sigma = 1.

\\ Z = \frac{\overline{X} - \mu}{\frac{\sigma}{\sqrt{n}}} [2]

From the question, we know that

  • The population mean is \\ \mu = 88 WPM
  • The population standard deviation is \\ \sigma = 14 WPM

We also know the size of the sample for this case: \\ n = 137 sixth graders.

We need to estimate the probability that a sample mean being greater than \\ \overline{X} = 89.87 WPM in the <em>distribution of sample means</em>. We can use the formula [2] to find this question.

The probability that the sample mean would be greater than 89.87 WPM

\\ Z = \frac{\overline{X} - \mu}{\frac{\sigma}{\sqrt{n}}}

\\ Z = \frac{89.87 - 88}{\frac{14}{\sqrt{137}}}

\\ Z = \frac{1.87}{\frac{14}{\sqrt{137}}}

\\ Z = 1.5634 \approx 1.56

This is a <em>standardized value </em> and it tells us that the sample with mean 89.87 is 1.56<em> standard deviations</em> <em>above</em> the mean of the sampling distribution.

We can consult the probability of P(z<1.56) in any <em>cumulative</em> <em>standard normal table</em> available in Statistics books or on the Internet. Of course, this probability is the same that \\ P(\overline{X} < 89.87). Then

\\ P(z

However, we are looking for P(z>1.56), which is the <em>complement probability</em> of the previous probability. Therefore

\\ P(z>1.56) = 1 - P(z

\\ P(z>1.56) = P(\overline{X}>89.87) = 0.0594

Thus, "The probability that the sample mean would be greater than 89.87 WPM" is about \\ P(z>1.56) = 0.0594.

5 0
3 years ago
Maria and Nate graphed lines on a coordinate plane. Maria's line is represented by the equation y = -5/6x +8. Nate's line is per
eduard

Answer:

c)   6x - 5y = 15

Step-by-step explanation:

Slope-intercept form of a linear equation:  y=mx+b

(where m is the slope and b is the y-intercept)

Maria's line:  y=-\dfrac{5}{6}x+8

Therefore, the slope of Maria's line is -\frac{5}{6}

If two lines are perpendicular to each other, the product of their slopes will be -1.

Therefore, the slope of Nate's line (m) is:

\begin{aligned}\implies m \times -\dfrac{5}{6} &=-1\\m & =\dfrac{6}{5}\end{aligned}

Therefore, the linear equation of Nate's line is:

y=\dfrac{6}{5}x+b\quad\textsf{(where b is some constant)}

Rearranging this to standard form:

\implies y=\dfrac{6}{5}x+b

\implies 5y=6x+5b

\implies 6x-5y=-5b

Therefore, <u>option c</u> could be an equation for Nate's line.

3 0
2 years ago
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