Answer: Manufacturing engineers may be responsible for solving production problems, conducting cost-benefit assessments, or designing and manufacturing goods and systems using computer-aided design software. Plant engineers and process engineers are two terms used by professionals in this industry. Manufacturing engineers are in charge of new and existing production lines' technical management, maintenance, and development. Employers are looking for people that are commercially aware and have good technical and analytical skills. They are in charge of keeping production costs low while preserving the product or service's quality, and they have considerable project expertise and insight.
Explanation: See above.
I hope this helps.
Answer:
class helloSarah {
public static void main(String [] args) {
Name = "Hello Sarah";
System.out.print(Name);
}
}
Explanation:
<em>The question seem incomplete; However, since the program is incorrect, I'll assume the question is to correct the given code;</em>
The program segment was written in Java and the correct program is in the answer section
<u>See bold texts for line by line explanation </u>
This line declares the class name
<em>class helloSarah {</em>
This line declares the main method of the program
<em>public static void main(String [] args) {</em>
This line initializes string variable Name
<em>String Name = "Hello Sarah";</em>
This line prints the initialized variable
<em>System.out.print(Name);</em>
<em>}</em>
<em>}</em>
<em />
Answer:
9V
Explanation:
I'm not sure if this is correrct, but i assume you just do a loop in the path of D1 to the resistor to D3. Using kirchoff voltage law, they should sum up to 0. The forward voltage drop of each diode is already given so just sub those value i and solve for Vr (voltage drop over resistor).
10 - Vd1 - Vr - Vd3 = 0
10 - .3 - Vr - .7 = 0
Vr = 10 - .3 - .7 = 9V