Answer:
Explanation:
<u><em>General Considerations</em></u>
The design of the yard will affect the natural surface and subsurface drainage pattern of a watershed or individual hillslope. Yard drainage design has as its basic objective the reduction or elimination of energy generated by flowing water. The destructive power of flowing water increases exponentially as its velocity increases. Therefore, water must not be allowed to develop sufficient volume or velocity so as to cause excessive wear along ditches, below culverts, or along exposed running surfaces, cuts, or fills.
A yard drainage system must satisfy two main criteria if it is to be effective throughout its design life:
1. It must allow for a minimum of disturbance of the natural drainage pattern.
2.It must drain surface and subsurface water away from the roadway and dissipate it in a way that prevents excessive collection of water in unstable areas and subsequent downstream erosion
The diagram below ilustrate diffrent sturcture of yard to be consider before planing to utiliza rainwater
Answer:
7.72 seconds
The answer is not realistic as the time is very less to reach to a speed of 100 km/hr
also, we have not taken other factors into consideration like wind drag etc.
Explanation:
Data provided in the question:
Mass of the engine = 1500 kg
Power rating = 75 kW = 75,000 W
Initial speed, v₁ = 0
Final speed = 100 km/hr =
= 27.78 m/s
Now,
Power = Work done ÷ Time
also,
Work done = Final energy - Initial energy
= 
= 
= 578703.70 J
thus,
75,000 = 578703.70 ÷ time
or
time = 7.716 s ≈ 7.72 seconds
The answer is not realistic as the time is very less to reach to a speed of 100 km/hr
also, we have not taken other factors into consideration like wind drag etc.
<h2>
WATER</h2>
<em>Explanation:</em>
<em> </em><em>Water is the only common substance that is naturally found as a solid, liquid or gas. Solids, liquids and gases are known as states of matter.</em>
Answer:
a)m = 247.43 kg
b) m = 123.71 kg
Explanation:
a)
Given data:
volume =0.8 m^3
P = 18,000 kPa
T =35 degree C = 308 K
By ideal gas equation we have following relation
PV = mRT
where R is gas constant



m = 247.43 kg
b)
when pressure = 9000 kPa
from ideal gas equation
PV = mRT
where R is gas constant



m = 123.71 kg