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Vinvika [58]
3 years ago
9

please help me to find the answer to this electronics topic test questions. My priority finds the answer to this question if you

explained more detail I will also be happy more. Thank you by now

Engineering
1 answer:
liq [111]3 years ago
8 0

Answer:

9V

Explanation:

I'm not sure if this is correrct, but i assume you just do a loop in the path of D1 to the resistor to D3. Using kirchoff voltage law, they should sum up to 0. The forward voltage drop of each diode is already given so just sub those value i and solve for Vr (voltage drop over resistor).

10 - Vd1 - Vr - Vd3 = 0

10 - .3 - Vr - .7 = 0

Vr = 10 - .3 - .7 = 9V

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It is desired to produce and aligned carbon fiber-epoxy matrix composite having a longitudinal tensile strength of 610 MPa. Calc
julia-pushkina [17]

Answer:

volume fraction of fibers is 0.4

Explanation:

Given that for the aligned carbon fiber-epoxy matrix composite:

Diameter (D) = 0.029 mm

Length (L) = 2.3 mm

Tensile strength (\sigma_{cd}) = 610 MPa

fracture strength (\sigma_f) = 5300 MPa

matrix stress (\sigma_m) =  17.3 MPa

fiber-matrix bond strength (\tau_c) = 19 MPa

The critical length is given as:

L_C=\sigma_f(\frac{D}{2\tau_c} )=5300*10^6(\frac{0.029*10^{-3}}{19*10^6} )=8.1*10^{-3}=8.1mm

Since the critical length is greater than the length, the aligned carbon fiber-epoxy matrix composite can be produced.

The longitudinal strength is given by:

\sigma_{cd}=\frac{L*\tau_c}{D} .V_f+\sigma_m(1-V_f)

making Vf the subject of the formula:

V_f=\frac{\sigma_{cd}-\sigma_m}{\frac{L*\tau_c}{D} -\sigma_m}

Vf is the volume fraction of fibers.

Therefore:

V_f=\frac{\sigma_{cd}-\sigma_m}{\frac{L*\tau_c}{D} -\sigma_m}=\frac{610*10^6-17.3*10^6}{\frac{2.3*10^{-3}*19*10^6}{0.029*10^{-3}}-17.3*10^6} } =0.4

volume fraction of fibers is 0.4

8 0
3 years ago
A mass of 5 kg of saturated water vapor at 100 kPa is heated at constant pressure until the temperature reaches 200°C.
Alex73 [517]

Answer: you can watch a video on how to solve this question on you tube

6 0
4 years ago
Consider a cylindrical nickel wire 1.8 mm in diameter and 2.6 × 104 mm long. Calculate its elongation when a load of 290 N is ap
telo118 [61]

Answer:

e = 3.97*10^-4

Explanation:

1.8 mm = 0.0018 m

2.6*10^4 mm = 26 m

Elongation is The ratio between the stretched length and the original length.

e = L/L0

This is calculated with Hooke's law:

e = σ/E

Where

σ: normal stress

E: elastic constant

σ = P/A

Where

P: normal load

A: cross section

A = π/4 * d^2

Therefore:

e = P / (A * E)

e = 4 * P / (π * d^2 * E)

e = 4 * 290 / (π * 0.0018^2 * 207*10^9) = 3.97*10^-4

8 0
3 years ago
Do all websites use the same coding to create?
Sonbull [250]

Answer:

yes.

Explanation:

because all websites use coding

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3 years ago
Design an algorithm for computing √n
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Positive integer n design an algorithm
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