The relative velocity is defined as the velocity of an object with respect to another observer. It is the time rate of change of relative position of one object with respect to another object.
<h3>What is the relative velocity of A with respect to B?</h3>
The relative velocity of A with respect to B= velocity of the body A – velocity of the body B.
<h3>What is relative velocity and its formula?</h3>
The relative velocity formula is expressed as. V → = V A B → + V B C → Where. VAB is the velocity with respect to A and B, VBC is the velocity with respect to B and C and VAC is the velocity with respect to A and C.
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Answer:
time = 224 days
Explanation:
given data
thick = 30 m
piezometers = 280 m
head between two = 1.4 m
aquifer hydraulic conductivity = 50 m
porosity = 20%
solution
we get here average pole velocity that is get by using Darcy law that is
Va =
................1
here Va is average pole velocity and k is hydraulic conductivity and
is porosity
here v is =
...........2
v = 50 ×
v = 0.25 m/day
and here average linear velocity Va will be
Va =
Va =
Va = 1.25 m/day
travel time for water will be
time =
time = 224 days
The engineering design process is a common series of steps that engineers use in creating functional products and processes.
Steps of the Engineering Design Process
Define the Problem. The engineering design process starts when you ask the following questions about problems that you observe: ...
Do Background Research. ...
Specify Requirements. ...
Brainstorm Solutions. ...
Choose the Best Solution. ...
Develop the Solution. ...
Build a Prototype. ...
Test and Redesign.
Process Engineer responsibilities include:
Developing, configuring and optimizing industrial processes from inception through to start up and certification. Assessing processes, taking measurements and interpreting data. Designing, running, testing and upgrading systems and processes.
Hope it helps
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Answer:
0.948 Btu
Explanation:
1 Btu = 1055 J so
= 0.948 Btu
Answer:
Magnitude of velocity when s is 10 m= 4.58m/s
Magnitude of acceleration when s is 10 m = 0.653 m/s²
Explanation:
Radius of circular path = 50m
Speed = 4m/s
increase in acceleration = (0.05s)m/s²
speed and acceleration when s is 10 m = ?
Magnitude of Velocity:
From third equation of motion
![v_{f}^{2}-v_{i}^{2}=2aS\\\\v_{f}=\sqrt{2aS+v_{i}^{2}} \\\\v_{f}=\sqrt{2(0.05)(10)+(4)^{2}} \\\\v_{f}=4.58\,m/s](https://tex.z-dn.net/?f=v_%7Bf%7D%5E%7B2%7D-v_%7Bi%7D%5E%7B2%7D%3D2aS%5C%5C%5C%5Cv_%7Bf%7D%3D%5Csqrt%7B2aS%2Bv_%7Bi%7D%5E%7B2%7D%7D%20%5C%5C%5C%5Cv_%7Bf%7D%3D%5Csqrt%7B2%280.05%29%2810%29%2B%284%29%5E%7B2%7D%7D%20%5C%5C%5C%5Cv_%7Bf%7D%3D4.58%5C%2Cm%2Fs)
Magnitude of Acceleration:
![a=\sqrt{a_{t}^{2}+a_{n}^{2}}--(1)](https://tex.z-dn.net/?f=a%3D%5Csqrt%7Ba_%7Bt%7D%5E%7B2%7D%2Ba_%7Bn%7D%5E%7B2%7D%7D--%281%29)
The tangential component of acceleration is
![a_{t}=(0.05)(10)\\a_{t}=0.5\,m/s^{2}](https://tex.z-dn.net/?f=a_%7Bt%7D%3D%280.05%29%2810%29%5C%5Ca_%7Bt%7D%3D0.5%5C%2Cm%2Fs%5E%7B2%7D)
The normal component of acceleration is
![a_{n}=\frac{v^{2}}{R}\\\\a_{n}=\frac{16}{50}\\\\a_{n}=0.42\,m/s^{2}](https://tex.z-dn.net/?f=a_%7Bn%7D%3D%5Cfrac%7Bv%5E%7B2%7D%7D%7BR%7D%5C%5C%5C%5Ca_%7Bn%7D%3D%5Cfrac%7B16%7D%7B50%7D%5C%5C%5C%5Ca_%7Bn%7D%3D0.42%5C%2Cm%2Fs%5E%7B2%7D)
Substituting tangential and normal component in (1)
![a=\sqrt{(0.5)^{2} +(0.42)^{2} }](https://tex.z-dn.net/?f=a%3D%5Csqrt%7B%280.5%29%5E%7B2%7D%20%2B%280.42%29%5E%7B2%7D%20%7D)
a=0.653 m/s²