Complete Question:
A metal plate of 400 mm in length, 200mm in width and 30 mm in depth is to be machined by orthogonal cutting using a tool of width 5mm and a depth of cut of 0.5 mm. Estimate the minimum time required to reduce the depth of the plate by 20 mm if the tool moves at 400 mm per second.
Answer:
26 mins 40 secs
Explanation:
Reduction in depth, Δd = 20 mm
Depth of cut,
Number of passes necessary for this reduction,
n = 20/0.5
n = 40 passes
Tool width, w = 5 mm
Width of metal plate, W = 200 mm
For a reduction in the depth per pass, tool will travel W/w = 200/5 = 40 times
Speed of tool, v = 100 mm/s
minimum time required to reduce the depth of the plate by 20 mm:
number of passes * Time/pass
n * Time/pass
40 * 40
1600 = 26 mins 40 secs
Answer:
The average loss for this device is $10.90
Explanation:
Given data
Specification = 24 +/- 0.4 Amps
average quality cost = $32.00
average value y = 23.9
standard deviation s = 0.211 Amps
32 = k(24.4 - 24)²
32 = k(0.4)² = k(0.16)
k = 32/0.16 = 200
To evaluate average loss, use
L = k{s² + (y - T)²}
T = 24A
L = 200{0.211² + (23.9 - 24)²}
L = $10.90
The average loss for this device is $10.90
Answer:
34.2 Cm
Explanation:
Lets take, Snell's law
C = 48.75°
To find radius,r of the circle, we have:
r = H tanC
Where H = 15 cm
r = 15 * tan048.75°
= 17.1 cm
Diameter = 2r
= 2 * 17.1cm
= 34.2 cm
The diameter of the circle is 34.2cm
Answer:
a) Specific Gravity G = 2.624
b) Absorption of the mixture = 2.7%
Explanation:
Given that:
Bulk specific gravity of aggregate A is G₁ = 2.491
Bulk specific gravity of aggregate B is G₂ = 2.773
Absorption percentage of aggregate A = 0.8%
Absorption percentage of aggregate B = 4.6%
Answer:
F= 5 N
V= 4 m/s
Explanation:
Given that fluid is Newtonian fluid .As we know that for Newtonian fluid the shear stress given as
We also know that
Force = shear stress x area of plate
Now by putting the values
Here velocity of fluid profile is linear.
τ= 2.5 Pa
So force = 2.5 x 2
F= 5 N
Now when fluid is replaced by another fluid but force is constant.The height of plate is also constant.
Lets take velocity of fluid is V in the new condition
So we can say that
Now by putting the value
50 x 0.4 = 5 x V
V= 4 m/s