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vazorg [7]
3 years ago
8

Help this due today

Mathematics
1 answer:
Romashka [77]3 years ago
8 0

Answer:

the answer is b because a squared plus b squared is c squared

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Is the following statement true or false?<br> A line is zero-dimensional.<br> true<br> false
garik1379 [7]
Answer:
False

Explanation:
Zero-dimensional would be a point.
One-Dimensional would be a line.
Two-Dimensional would be a plane.
Three-Dimensional would be a shape.
7 0
2 years ago
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What is the value of h?
nekit [7.7K]

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10ft

Step-by-step explanation:

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2 years ago
Convert the rectangular equation to polar form. assume a is less than 0.<br> x=10
Ilia_Sergeevich [38]
R cos(t) =10 r = 10/cos(t)
5 0
3 years ago
Find the probability that the hitter makes 10 outs in 10 consecutive​ at-bats, assuming​ at-bats are independent events.​ Hint:
emmainna [20.7K]

Answer:

0.037

Step-by-step explanation:

If the hitter makes an out 72​% of the time, then the probabilty that he makes hit in 1 at-bat is p=0.72 and the probabilty that he doesn't make hit in 1 at-bat is q=1-p=1-0.72=0.28.

The probability that the hitter makes 10 outs in 10 consecutive​ at-bats, assuming​ at-bats are independent events is

P=p^{10}=(0.72)^{10}\approx 0.037.

5 0
3 years ago
How many different 4 digit even numbers can be written using 0,5,6,3,8,7?
kherson [118]

Step-by-step explanation:

I assume the digits cannot be repeated in the numbers.

and that we don't want any numbers that start with 0, as that would be considered a 3- digit number, right ?

so, under these assumptions we have the question of in how many ways can we pull 4 digits out of 6.

if the sequence of the pulled digits would not matter, it would be combinations C(6, 4).

but because we are building actual numbers, the sequence does matter, and we use permutations P(6, 4).

P(6, 4) = 6!/(6-4)! = 6!/2! = 6×5×4×3 = 360

so, we can create 360 different numbers.

but not all of them are wanted.

we don't want the ones that start with 0. how many are those ?

since we are handling all digits in the same way and priority, there are an equal amount of numbers that start with a 0, or a 5, or a 6, or a 3, or a 8, or a 7.

so, 1/6 of the 360 numbers start with a 0, and we need to subtract them :

360 - 60 = 300 really 4-digit numbers

and from these 300 we only want even numbers. that means they can only end with 0, 6 or 8.

in the same way as for the first position, we have 1/6 of the more 300 numbers that end with one of these digits.

we allow 3 digits, so we have

3×1/6 × 300 = 1/2 × 300 = 150

that means we can write 150 different 4-digit even numbers out of these 6 digits.

6 0
2 years ago
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