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Andreas93 [3]
3 years ago
9

What property is (C+2+0=c+2

Mathematics
1 answer:
VashaNatasha [74]3 years ago
7 0

Answer:

commutative property is C+2+0=C+2

(As a+b=b+a is the law of commutative property of addition )

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Is this a function why or why not?
Naily [24]
Yes, it is a function because each input has only one output.

Hope it helps!
6 0
3 years ago
What is 3 and 1 tenth as a desimal
Bess [88]

Representing 3 and one tenth as decimal by 3.1

<u>Step-by-step explanation:</u>

Here 3 is the whole number.

1 tenth is nothing but \frac{1}{10}.

\frac{1}{10} = 0.1

When we write numerals with tenths using the decimals we can use a decimal point also the tenths positioned to the right of the decimal point. The tenth place is denoted as immediately right to the decimal point.

So it is represented as 3.1.

5 0
4 years ago
At a large Midwestern college, 4 % 4% of the students are Hispanic. A random sample of 20 students from the college is selected.
oee [108]

Answer:

option a

Step-by-step explanation:

given that at a large Midwestern college, 4 % 4% of the students are Hispanic.

A  random sample of 20 students from the college is selected.

We have each student is independent of the other to be hispanic

p = success = being hispanic = 0.04 while

q = failure = being non hispanic = 0.96

X - no of hispanics is thus binomial with p = 0.04 and n =20 (sample size)

Since X is binomial

Var(x) = npq = 0.768

Std dev (x) = Square root of variance = \sqrt{0.768} \\=0.8764

rounded off it gives 0.88

So option a is right

4 0
3 years ago
Suppose x and y are nonzero vectors in an inner product space. Show that x and y are orthogonal if and only if ||x+y|| = ||x-y||
harkovskaia [24]

Answer:

Step-by-step explanation:

Suppose x and y are nonzero vectors in an inner product space.

Let us assume that x and y are orthogonal

i.e. innter product is 0.

This implies dot product of x and y is 0

Then x.y =0

i.e. x^2+y^2 +2x.y = x^2+y^2-2x.y\\||x+y||=||x-y||

Proved

Converse part:

Let ||x+y||=||x-y||

Square also would be equal

||x+y||^2=||x-y||^2\\||x||^2+||y||^2+2x,t=||x||^2+||y||^2-2x.y\\x.y =0

Hence inner product of x and y is 0

7 0
3 years ago
Hello, happy Friday, I am just here with some geometry questions.
Genrish500 [490]

Answer:

x=4

Step-by-step explanation:

By the Triangle Proportionality Theorem:

\displaystyle \frac{x}{12}=\frac{x+1}{15}

By cross-multiplication:

\displaystyle 12(x+1)=15(x)

Distribute:

12x+12=15x

Subtract 12x from both sides:

12=3x

Hence:

x=4

5 0
3 years ago
Read 2 more answers
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