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2 years ago

David owns a clothes shop on Rolling Street. Which of the following is a statistical question that David can be asked?

Mathematics

2 answers:

Leni [432]2 years ago

4 0

Answer:The correct answer is A

Step-by-step explanation:

Because a Statistical question is a question that have a vary of answers that can be answered by collecting data. A non-statistical question is a question that can be answered with ONE answer. For an example of non-statical is how much does that brick weigh. A is correct because it has variety of answers and and is also answered by collecting data

valina [46]2 years ago

3 0

Answer:

i would say d.

Step-by-step explanation:

because depending on whether he is a competitor seller go's by the competition prices they might want to know how low is his cheapest shirt they might want to know which one is cheaper, and he would also keep track of his sales

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3. How many turning points does the graph P(x) = (x-7)(x + 4)(x-2)

mixer [17]

Answer:

The y intercept in P(x) =4

1.C

3.B

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3 years ago

Which of the following is a polynomial with roots

PtichkaEL [24]

$a(x-x_1)(x-x_2)(x-x_3)\\\\x_1=-\sqrt3;\ x_2=\sqrt3;\ x_3=-2;\ a=1\\\\subtitute\\\\(x+\sqrt3)(x-\sqrt3)(x+2)=(x^2-3)(x+2)\\\\=\boxed{x^3+2x^2-3x-6}\to\fbox{B.}$

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2 years ago

Read 2 more answers

Without multiplying, tell whether the product 0.644 x 0.25 will be greater than 1 or less than 1? Explain how you know.

stepladder [879]

Answer:

Less than 1

Step-by-step explanation:

As 0.644 and 0.25 are less than 1, then

$0.644=\frac{1}{p}$

$0.25=\frac{1}{q}$

where p and q are greater than 1

then

$0.644\times0.24=\frac{1}{p.q}$

But p.q is greater than 1, so 1/(p.q) is smaller than 1

7 0

2 years ago

Read 2 more answers

If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle? A) (x

Andrei [34K]

Answer:

$\large\boxed{A.\ (x+6)^2+(y+10)^2=20}$

Step-by-step explanation:

The standard form of an equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the endpoints of the diameter of a circle (-8, -6) and (-4, -14).

The midpoint of a diameter is a center of a circle.

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$x=\dfrac{-8+(-4)}{2}=\dfrac{-12}{2}=-6\\\\y=\dfrac{-6+(-14)}{2}=\dfrac{-20}{2}=-10$

We have h = -6 and k = -10.

The radius is the distance between a center and the point on a circumference of a circle.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute (-6, -10) and (-8, -6):

$r=\sqrt{(-8-(-6))^2+(-6-(-10))^2}=\sqrt{(-2)^2+4^2}=\sqrt{4+16}=\sqrt{20}$

Finally we have

$(x-(-6))^2+(y-(-10))^2=(\sqrt{20})^2\\\\(x+6)^2+(y+10)^2=20$

5 0

3 years ago

Read 2 more answers

Is there more than one possible answer to part a

Maksim231197 [3]

There are apparently a huge number of correct answers ...
the statement of part-a that you've attached has so few
restrictions, requirements, or specifications.

4 0

3 years ago