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nirvana33 [79]
3 years ago
7

What is 3y^2-y-2 in factored form?

Mathematics
1 answer:
GaryK [48]3 years ago
7 0

BY USING MIDDLE TERM SPLITTING,

3y^2-(3y-2y)-2

(3y^2-3y)+(2y-2)

3y(y-1)+2(y-1)

(3y+2)(y-1)

HOPE THIS WILL HELP U

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Create two whole number division problems
AlekseyPX
98 divided by 2 equals 49 55 divided by 5 equals 11
3 0
3 years ago
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Can someone help? This is so hard
Sunny_sXe [5.5K]

Answer:

#1 x = 31°

#2 x = 125°

Step by Step Explanation:

#1

  • By the theorem of intersecting secants outside of the circle, we have:

  • x=\frac{1}{2}(103\degree-41\degree)

  • \implies x=\frac{1}{2}(62\degree)

  • \implies \red{\bold{x=31\degree}}

#2

  • By the theorem of intersecting chords, we have:

  • x=\frac{1}{2}(96\degree+154\degree)

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4 0
2 years ago
Work Out<br> 8^1/3 ÷ 5^-2
svp [43]
I believe the answer would be 50

explanation:

calculate
2 ÷ 5^-2

use negative power rule x^-a = 1/x^a
2 ÷ 1/5^2

simply 5^2 to 25
2 ÷ 1/25

use this rule a ÷ b/c = a • c/b
2 • 25

simplify
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5 0
3 years ago
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Solve for x . Leave your answer in the simplest form
Alisiya [41]

Hello!

Here we are given a composite shape, meaning that we can divide this shape up into ways that we are given formulas to solve for legs and such.

I can see here that this can be divided into a triangle and a rectangle using a horizontal line.

The leg lengths of this triangle would be 9, because it is congruent to the bottom side of the rectangle, and 7, because it is the left side minus the right side.

This would also make a right triangle, meaning we could solve for the hypotenuse utilizing the Pythagorean Theorem.

a^2+b^2=c^2

6^2+7^2=c^2

36+49=c^2

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Which is in simplest radical form.

Hope this helps!

3 0
3 years ago
A standard deck of playing cards has 13 cards in each of four suits: hearts, clubs, diamonds, and spades. Two cards are chosen f
Aloiza [94]

Answer:

Probability of choosing one club and one spade = 0.6025

Step-by-step explanation:

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For the first event

Probability of choosing a club

Toatal club = 13 cards

Probability of choosing a club

= 13/52

Probability of choosing a club

= 1/4

Probability of choosing a club

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For the second event

Probability of choosing a spade

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Probability of choosing a spade

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= 1/4

Probability of choosing a spade = 0.25

Probability of both = 0.25*0.25

Probability of both = 0.6025

5 0
3 years ago
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