Answer:
The first digit of a two digit number can be any of digits 1 - 9. It cannot be 0 though. Therefore there are 9 possible digits for the first place.
There are 5 possible digits for the second position. The two digit number has to be odd and therefore the final digit must be 1,3,5,7 or 9
Therefore for each and every one of the nine first digits there are 5 digits that the second can be.
Therefore ANSWER = 9 * 5 = 45 possible permutations.
2. The largest two digit number = 99
Subtract 57 and you get 42
ANSWER = 42
The forty two numbers are 58 ,59, 60, 61......98, 99
Answer:
d(63)=21,420m
Step-by-step explanation:
d(t)=340t
D=Distance
T=Time
D(63)=21,420
Divide 1080 by 1+3+5 which is 9
120 is 1
360 is 3
600 is 5
120:360:600
Step-by-step explanation:
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Answer:
14
Step-by-step explanation:
21 divided by 3 =7 7 per 1/3
7x2=14
