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2 years ago

Convert the fraction to a decimal. 4 6/25

Mathematics

1 answer:

galina1969 [7]2 years ago

8 0

Answer:

4.25

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Sheldon also picks tomatoes from his garden. He picked 4 4/10 but 1.5 were rotten and had to be thrown away. How many kilograms

velikii [3]

Given:

Number of tomatoes Sheldon picks = $4\dfrac{4}{10}$ kg

Rotten tomatoes = 1.5 kg

To find:

How many kilograms of tomatoes were not rotten?

Solution:

Number of tomatoes Sheldon picks = $4\dfrac{4}{10}$ kg

= $\dfrac{4(10)+4}{10}$ kg

= $\dfrac{40+4}{10}$ kg

= $\dfrac{44}{10}$ kg

= $4.4$ kg

Rotten tomatoes = 1.5 kg

Remaining tomatoes which are not rotten is

Required tomatoes = Tomatoes Sheldon picks - Rotten tomatoes

= $4.4-1.5$

= $2.9$ kg

Therefore, the tomatoes which were not rotten is 2.9 kg.

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3 years ago

3. The graph f(x) = -x - is shown below.

Troyanec [42]

Answer: the answer is 2

Step-by-step explanation:

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2 years ago

Which statements about the Extreme Value theorem are true?

SCORPION-xisa [38]

Answer:

do you have any statments?

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2 years ago

Find the solution of the system of equations. 3x+3y= 3x+3y= \,\,42 42 x-3y= x−3y= \,\,-22 −22

oee [108]

Answer:

x = 5 y = 9

Step-by-step explanation:

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2 years ago

Suppose that 5 out of 13 people are to be chosen to go on a mission trip. In how many ways can these 5 be chosen if the order in

algol [13]

5 People can be chosen in 1287 ways if the order in which they are chosen is not important.

Step-by-step explanation:

Given:

Total number of students= 13

Number of Students to be selected= 5

To Find :

The number of ways in which the 5 people can be selected=?

Solution:

Let us use the permutation and combination to solve this problem

$nCr=\frac{(n)!}{(n-r)!(r)!}$

So here , n =13 and r=5 ,

So after putting the value of n and r , the equation will be

$13C_5=\frac{(13)!}{(13-5)!(5)!}$

$13C_5=\frac{(13 \times12 \times11 \times10 \times9 \times8\times7 \times6 \times5 \times4 \times3 \times2 \times1)}{(8 \times7 \times6 \times5 \times4 \times3 \times2 \times1)(5 \times4 \times3 \times2 \times1)}$

$13C_5=\frac{(13 \times12 \times11 \times10 \times9 )}{((5 \times4 \times3 \times2 \times1)}$

$13C_5=\frac{154440}{120}$

$13C_5= 1287$

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3 years ago