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Luden [163]
3 years ago
15

GE produces 5 different sizes of TVs using 2 machines. Different sizes of TVs take different amount of time to get processed at

each of the two machines, and bring in different amount of profit for the company per unit. GE has a limited amount of time to process TVs during each month but would like to find out how many of each size of TV to produce each month to maximize its total profit.
How many decision variables are needed to properly formulate this problem?

Select one:

a. 2

b. 7

c. 5

d. Cannot be determined with the given amount of information

e. 10
Mathematics
1 answer:
OLga [1]3 years ago
8 0

Answer:

Option # C: 5

Step-by-step explanation:

Decision variables, as the name imply are entities that can have different values in the given scenario and which in turn produce different outcomes. For our question, the variables are the sizes of TVs available, as the production time and profit depend on the sizes. Hence, TV sizes (i.e. 5) are our decision variables.

Furthermore, it does not matter on which machine the TVs are being manufactured as they will take identical time for same TV size. Thus we do not consider the number of machines as our decision variables.

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Reptile [31]

just multiply 45 time 31!

3 0
3 years ago
Casey orders 3 pizzas and 2 orders of breadsticks for a total of 30.00. Rachel orders 2 pizzas and 3 orders of breadsticks for 2
barxatty [35]

Answer:

8

Step-by-step explanation:

x=pizza

y= breadsticks

3x+2y=30

2x+3y=25

first we myltiply the top equation with 3 and then w emultiply the lower equation with -2 so it is

9x+6y=90

-4x-6y= -50

now we can add them together and the y contracts

5x=40

now we divide it by 5

x=8

So pizza costs 8

3 0
3 years ago
Х
scZoUnD [109]

Step-by-step explanation:

m=y2-y1/x2-x1

m=0-(-2)/4-2

m=2/2

m=1

5 0
3 years ago
The number of cars running a red light in a day, at a given intersection, possesses a distribution with a mean of 3.6 cars and a
Iteru [2.4K]

Answer:

X \sim N(3.6,5)  

Where \mu=3.6 and \sigma=5

Then we have:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

With the following parameters:

\mu_{\bar X}= 3.6

\sigma_{\bar X} = \frac{5}{\sqrt{100}}= 0.5

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the number of cars running a red light of a population, and for this case we know the distribution for X is given by:

X \sim N(3.6,5)  

Where \mu=3.6 and \sigma=5

Since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

With the following parameters:

\mu_{\bar X}= 3.6

\sigma_{\bar X} = \frac{5}{\sqrt{100}}= 0.5

5 0
3 years ago
Liam sits on a merry-go-round at the local fair. He completes 12 revolutions in 4
Musya8 [376]

Answer:

1/3 min ( = 20 seconds)

Step-by-step explanation:

The period of the ride is the time he takes to complete 1 revolution

We are given:

12 revolutions -------> takes 4 min

1 revolution ------> takes 4/12 = 1/3 min  (= 20 seconds)

7 0
3 years ago
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