What a delightful little problem ! (Partly because I could see
right away how to do it, and had the answer in a few minutes,
after a lot of impressive-looking algebra on my scratch-paper.)
Three consecutive integers are . . . x, x+1, and x+2
The smallest two are . . . x and x+1
Their product is . . . . . x(x+1)
5 times the largest one is . . . 5(x+2)
5 less than that is . . . . . . 5(x+2)-5
Now, the conditions of the problem say that <u>x (x + 1) = 5 (x+2) - 5</u>
THAT's the equation we have to solve, to find 'x' .
Eliminate parentheses: x² + x = 5x + 10 - 5
Combine like terms: x² + x = 5x + 5
Subtract 5x from each side: x² - 4x = 5
Subtract 5 from each side: <u>x² - 4x - 5 = 0</u>
You could solve that by factoring it, or use the quadratic equation.
Factored, it says that (x + 1) (x - 5) = 0
From which <em>x = -1</em>
and <em>x = +5</em>
We only want the positive results, so our three consecutive integers are
5, 6, and 7 .
To answer the question, the smallest one is <em><u>5 </u></em>.
<u>Check</u>:
5 x 6 ? = ? (7 x 5) - 5
30 ? = ? (35) - 5
30 = 30
yay !
Answer:
79
Step-by-step explanation:
To find the value of
, when x = 3, simply plug in the value of x in the expression and solve as follows:




The value of
, when x = 3, is 79
Answer:
x = 5/2
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
12x - 30 = 2x - 5
<u>Step 2: Solve for </u><em><u>x</u></em>
- Subtract 2x on both sides: 10x - 30 = -5
- Add 30 to both sides: 10x = 25
- Divide 10 on both sides: x = 5/2
There are 6 possibilities.
Rhino, elephant, lion
rhino, lion, elephant
elephant, lion, rhino
elephant, rhino, lion
Lion, rhino, elephant
lion, elephant, rhino
Answer:
84.85cm
Step-by-step explanation:
Let the sides of the square be x
The perimeter of the square = 4x
Get x using the pythagoras theorem
x^2 + x^2 = 30^2
2x^2 = 900
x^2 = 450
x = 21.21cm
Perimeter of the plate = 4(21.21)
Perimeter of the plate = 84.85cm