Write a fraction that is equivalent to 6 explain why the fraction is equivalent to 6

In 1984 a locally-owned car company sold 2,743 cars. In 2003, the car sales rose to 4,069. What was the average rate of change f

tatiyna

Answer:

70 cars per year.

Step-by-step explanation:

Given:

In 1984 a locally-owned car company sold 2,743 cars.

In 2003, the car sales rose to 4,069.

Question asked:

What was the average rate of change for the total number of cars sold?

Solution:

In 2003 number of cars sold = 4069

In 1984 number of cars sold = 2743

Change in the number of car sold = 4069 - 2743

= 1326

Now, time interval between 2003 and 1984 = 19

$The\ average\ rate\ of\ change=\frac{Change\ in\ the\ number\ of\ car\ sold}{Time \ interval}$

$=\frac{1326}{19} \\=69.789\\\\=70\ cars\ per\ year\ (approx)$

Thus, the average rate of change for the total number of cars sold is 70 cars per year.

7 0

3 years ago

Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. Whe

kherson [118]

Answer:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$

$n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11$

And rounded up we have that n=1068

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.03$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

We don't have a prior estimation for the proportion $\hat p$ so we can use 0.5 as an approximation for this case

And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11$

And rounded up we have that n=1068

5 0

3 years ago

Ok ok on Lapsus also so <br> I ready

Juli2301 [7.4K]

Answer:

8 dollars per hour

Step-by-step explanation:

If you divide 18 to 144 the answer is 8

8 0

2 years ago

Read 2 more answers

The sum of two numbers is 62, and their difference is 12. What are the numbers?

nordsb [41]

X+y=62 ; x-y=12 Solve for x in one equation and plug that value into the other equation. ===> x=12+y ; 12+y+y=62 Subtract 12 to both sides (2y=50), then divide by 2 to find y (y=25). Now, plug 25 as y into x=12+y, getting x=37. Your two numbers are 37 and 25.

6 0

3 years ago

Read 2 more answers

Mr. Birdie has worked hard as a Math teacher all his

Nikitich [7]

Answer:

You'll likely need assets worth 10 to 16 times your salary by the time you leave your job. A 45-year-old making $120,000 who hopes to retire at age 60, say, should already have nearly $700,000 set aside. (See the Retire Early calculator.) You can get by with less if you'll have other sources of income.

6 0

3 years ago