<span>-- the product of the net charges on the objects;. -- the distance between the centers of their net charges. (Pretty much identical to the formula for gravitational force)</span>
(a) time taken for the car to accelerate from v to 2v = t =
(b) velocity of the car moving at 2t seconds = ΔV = 2at
(a) we know that,
a=
where, is the final velocity
is the initial velocity
a = acceleration
t = time
Time taken to accelerate from V to 2V:
t =
(b) We know that,
a=
where, is the final velocity
is the initial velocity
a = acceleration
t = time
how fast is the car moving at 2t seconds after starting,
we can represent - = ΔV
at time = t= 2t, it becomes
a= = a = ΔV/2t
t= ΔV/2a
ΔV = 2at
<h3>What is acceleration?</h3>
Rate of change of velocity with time, both in terms of speed and direction is known as acceleration.
<h3>What is speed?</h3>
- the rate at which an object's location changes in any direction.
- The distance traveled in relation to the time it took to travel that distance is how speed is defined.
- Since speed simply has a direction and no magnitude, it is a scalar quantity.
To learn more about acceleration visit:
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Bob's average speed was 80 m/s.
His average velocity was 40 m/s East.
The magnitude of his velocity was almost 4 times as fast as Usain Bolt's world record in the 100 meters, or about 89 mph. His speed was double that.
To solve this problem we need the concepts of Energy fluency and Intensity from chemical elements.
The energy fluency is given by the equation
Where
The energy fluency
c = Activity of the source
r = distance
E = electric field
In the other hand we have the equation for current in materials, which is given by
Then replacing our values we have that
We can conclude in this part that 1.3*10^7Bq is the activity coming out of the cylinder.
Now the energy fluency would be,
The uncollided flux density at the outer surface of the tank nearest the source is
answer
6000 N
explanation
every force has an equal and opposite reaction force, so the force exerted by the truck on the car is the same as the force exerted by the car on truck
the force is 6000 N