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Law Incorporation [45]
3 years ago
14

A point charge of +1.0 µC is moved in the direction of an electric field, and it has a change in electric potential difference e

nergy of 10.0 J. What was the change in electric potential difference? 1 µC = 10^-6 C
1.0 × 108 V

1.0 × 107 V

+1.0 × 107 V

+1.0 × 108 V,
Physics
1 answer:
olga55 [171]3 years ago
7 0
The answer of <span> the change in electric potential difference is</span> -1.0 × 10^7 V.  It is defined as  the work done per unit charge. A potential difference of 1 V means that 1 joule of work is done per coulomb of charge or  1 V = 1 J C-1.  
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A 3.2 kg particle starts from rest at x = 0 and moves under the influence of a single force Fx = 4 + 15.7 x − 1.5 x 2 , where Fx
garik1379 [7]

Answer:

Explanation:

Work: This can be defined as the product of force and distance. The unit of work is Joules (J). it can be expressed mathematically as

W = F×d

or

W = \int\limits^b_a {Fx} \, dx.................................. Equation 1

Where b = upper limit, a = lower limit, Fx = expression of force.

<em>Given: a = 0 , b = 1.3 m, Fx = 4 + 15.7x - 1.5x²</em>

Substituting these values into equation 1

<em>W = \int\limits^a_b {(4 + 15.7x - 1.5x^{2} )dx} \,</em>

W = ᵇ[4x + 15.7x²/2-1.5x³/3 +C]ₐ

Work = upper limit - lower limit

Work = ᵃ[4x + 15.7x²/2 - 1.5x³/3 +C] - [4x + 15.7x²/2 + 1.5x³/3 +C]ᵇ............... Equation 2

Substituting the values of a and b into equation 2

Work = [4(1.3) + 15.7(1.3)²/2-1.5(1.3)³/3 + C] - [0 +C]

Work = [5.2 + 26.53 -3.29 + C] - C

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8 0
3 years ago
A student on an amusement park ride moves in circular path with a radius of 3.5 m once every 4.5 s. What is the tangential veloc
nata0808 [166]

Answer:

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Explanation:

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duration of the motion, t = 4.5 s

let the student's tangential velocity = v

The tangential velocity of the student is calculated as follows;

v = \frac{2\pi r}{t} \\\\v = \frac{2 \pi \times 3.5}{4.5} \\\\v = 4.89 \ m/s

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3 years ago
Three equal point charges, each with charge 2.00 μC , are placed at the vertices of an equilateral triangle whose sides are of l
oksano4ka [1.4K]

Answer:

Explanation:

Energy of system of charges

= k q₁q₂ / r₁₂ + k q₁q₃ / r₁₃ + k q₃q₂ / r₃₂

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= .432 J .

4 0
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