2 years ago

a swimmer swam 48 kilometers in d days. What is the value of the d if the swimmer swam an average of 3.2 kilometers daily?

Mathematics

1 answer:

lianna [129]2 years ago

6 0

Time= distance/speed

=48/3.2= 15

You might be interested in

How old am I if 500 reduced by 2 Times my age is 250

Gekata [30.6K]

Answer:Yes it is 250

Step-by-step explanation:

7 0

2 years ago

in a candy store a $5 jar of candy is labeled 50% off what is the discount what is the sale price of the jar of candy

beks73 [17]

The sale price would be $2.50.

3 0

2 years ago

What is the solution of the system x - 3y= -13

n200080 [17]

Answer:

There should be one more equation

Step-by-step explanation:

7 0

2 years ago

Fill in the table for side length and area of different squares.

Gnoma [55]

Answer:

0.09

Step-by-step explanation:

0.03 divided by 100

7 0

3 years ago

The product of 6g2 and -2g3 is equals to

ryzh [129]

Answer:

We conclude that:

$\left(6g^2\:\right)\times \left(-2g^3\right)=-12g^5$

Step-by-step explanation:

Given

6g²

-2g³

The product of 6g² and -2g³ can be determined by multiplying each other such as:

$(6g^2\:)\times \:(-2g^3)$

Apply the rule: a(-b) = -ab

$\left(6g^2\:\right)\times \left(-2g^3\right)=-6g^2\times \:\:2g^3$

Apply exponent rule: $a^b\times \:a^c=a^{b+c}$

$=-6g^{2+3}\times \:2$

$=-6g^5\times \:2$

$=-12g^5$

Therefore, we conclude that:

$\left(6g^2\:\right)\times \left(-2g^3\right)=-12g^5$

8 0

2 years ago