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Aleks04 [339]
2 years ago
10

If a jogger runs 2 miles and burns 185 calories, how many calories would he burn jogging 3 miles

Mathematics
2 answers:
Hunter-Best [27]2 years ago
7 0
Divide the calories by 2 to get the amount for 1 mile the multiply that by 3 to get your answer which is 277.5 calories
JulsSmile [24]2 years ago
6 0
He will burn 277.5 calories.
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What is the equation in slope-intercept form of the line that passes through the points (-4, 2) and (12, 6)? ​
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Answer:

Step-by-step explanation:

8 0
2 years ago
Use the data set to determine which statements are correct. Check all that apply. 35, 41, 18, 75, 36, 21, 62, 29, 154, 70 The me
stepladder [879]
The median is 38.5

The lower quartile is 29

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4 0
3 years ago
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Read 2 more answers
Mathematically verify the outlier(s) in the data set using the 1.5 rule.
statuscvo [17]

Given:

The data values are:

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

To find:

The outliers of the given data set.

Solution:

We have,

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

Divide the data set in two equal parts.

(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)

Divide each parenthesis in two equal parts.

(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)

Now,

Q_1=\dfrac{11+13}{2}

Q_1=\dfrac{24}{2}

Q_1=12

And

Q_3=\dfrac{16+16}{2}

Q_3=\dfrac{32}{2}

Q_3=16

The interquartile range is:

IQR=Q_3-Q_1

IQR=16-12

IQR=4

The data values lies outside the interval [Q_1-1.5IQR,Q_3+1.5IQR] are known as outliers.

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-1.5(4),16+1.5(4)]

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-6,16+6]

[Q_1-1.5IQR,Q_3+1.5IQR]=[6,22]

All the data values lie in the interval [6,22]. So, there are no outliers.

Hence, the correct option is 4.

3 0
2 years ago
Solve the equations<br>Y=2x-4, 3x+y=1​
liberstina [14]

Step-by-step explanation:

y = 2x - 4

3x + y = 1

y = 1 - 3x

Equating,

2x - 4 = 1 - 3x

2x + 3x =  1 + 4

5x = 5

x = 1

Placing it,

y = 1 - 3(  1)

y = 1 - 3

y =  - 2

6 0
3 years ago
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