Answer:
The dimension of the play area written algebraically is y²/2 + 9y
Step-by-step explanation:
Let the be x and the width be y
If the length is to be 9 feet longer than half the width,
hence y/2 + 9 = x
hence dimension of the area = (y/2 + 9) × y = y²/2 + 9y
Same question and answer as yours!
Answer:
4/15
Step-by-step explanation:
Answer:
- Earn a bachelor’s degree from an ABET-accredited universityEstablish licensure through the NCEES FE exam
- Earn a master’s degree in a sub-discipline of engineering
- Gain practical experience in the field
- Earn a professional engineering (PE) license in a sub-discipline of engineering
- Attain further professional certification or join professional societies
Step-by-step explanation: Hope this helped :)
Answer:
-5t^2 +2t -3
Step-by-step explanation:
Collect terms in the sum:
G+P = (3t^2 -5t +6) +(-8t^2 +7t -9) = (3-8)t^2 +(-5+7)t +(6-9)
= -5t^2 +2t -3
