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Roman55 [17]
3 years ago
8

A force of 19 newtons is applied on a cart of 2 kilograms, and it experiences a frictional force of 1.7 newtons. What is the acc

eleration of the cart
Physics
2 answers:
Dmitriy789 [7]3 years ago
5 0

Answer:

8.6 meters/second^2

Explanation:

Net force = 19 N - 1.7 N = 17.3 N

F = ma

17.3 N = 2 kg * a

a = 17.3 N / 2 kg  (N= kg*m/s^2)

a = 8.6 m/s^2

Umnica [9.8K]3 years ago
4 0
Frictional force always opposes applied force, so the net force on the cart would have to be 19N - 1.7N. The acceleration can then be solved by using the relation: F = ma. This is shown below:

Net force = 19 - 1.7 = 17.3 N

Acceleration = Force / mass
Acceleration = 17.3 / 2
Acceleration = 8.65 N/m
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Picture a long, straight corridor running east-west, with a water fountain located somewhere along it. Starting from the west en
Brut [27]

Answer:

The corridor's distance is "90 m".

Explanation:

  • She heads in the east directions but creates the first pause, meaning she crosses the distance 'x' in step 1.
  • Now, provided that perhaps the distance by her to another fountain or waterfall just after the first stop is twice as far away she traveled.
  • Because she moved the distance of 'x,' then, therefore, her distance towards the fountain of '2x.' She casually strolls and once again pauses 60 m beyond her stop.
  • The gap about her to the waterfall during that time approximately twice the distance and her to the eastern end of the hallway.
  • Assume her gap from either the east end of the platform seems to be 'y' at either the second stop, after which '2y' may become the distance between the 2nd pause and the waterfall.

Now,

⇒  2x + 2y = 60

⇒  x + y = 30

The total distance of the corridor will be:

=  x + 2x + 2y + y

=  3\times (x + y)

=  3\times 30

=  90 \ m

4 0
3 years ago
A man is standing on the shore of a beach, up to his knees in water. Every second two waves hit him. What is the frequency of th
laila [671]

Answer:

f = 2 Hz

Explanation:

The frequency of a wave is defined as the no. of waves passing per unit of time. Therefore, the frequency of a wave can be calculated by the following formula:

f = \frac{n}{t}

where,

f = frequency of the wave = ?

t = time passed = 1 s

n = no. of waves passing in time t = 2

Therefore,

f = \frac{2}{1\ s}

<u>f = 2 Hz</u>

3 0
3 years ago
Which of the following explains why metallic bonding only occurs between
Y_Kistochka [10]

Answer:

D. Metallic atoms have valence shells that are mostly empty, which

means these atoms are more likely to give up electrons and allow

them to move freely.

Explanation:

Metals usually contain very few electrons in their valence shells hence they easily give up these few valence electrons to yield metal cations.

In the metallic bond, metal cations are held together by electrostatic attraction between the metal ions and a sea of mobile electrons.

Since metals give up their electrons easily, it is very easy for them to participate in metallic bonding. They give up their electrons easily because their valence shells are mostly empty, metal valence shells usually contain only a few electrons.

3 0
3 years ago
He throws a second ball (B2) upward with the same initial velocity at the instant that the first ball is at the ceiling. c. How
Gwar [14]

Answer:

hello your question has some missing parts

A juggler performs in a room whose ceiling is 3 m above the level of his hands. He throws a ball vertically upward so that it just reaches the ceiling.

answer : c) 0.39 sec

               d)  2.25 m

               e) 1.92 m/sec

Explanation:

The initial velocity of the first ball = 7.67 m/sec ( calculated )

Time required for first ball to reach ceiling = 0.78 secs ( calculated )

Determine how long after the second ball is thrown do the two balls pass each other

Distance travelled by first ball downwards when it meets second ball can be expressed as : d = 1/2 gt^2 =  9.8t^2 / 2

hence d = 4.9t^2  ----- ( 1 )

Initial speed of second ball = first ball initial speed = 7.67 m/sec

3 - d = 7.67t - 4.9t  ---- ( 2 )

equating equation 1 and 2

3 = 7.67t   therefore t = 0.39 sec

Determine how far the balls are above the Juggler's hands ( when the balls pass each other )

form equation 1 ;

d = 4.9 t^2 = 4.9 *(0.39)^2 = 0.75 m

therefore the height the balls are above the Juggler's hands is

3 - d = 3 - 0.75 = 2.25 m

determine their velocities when the pass each other

velocity = displacement / time

velocity = d / t = 0.75 / 0.39 sec  = 1.92 m/sec

7 0
3 years ago
How many digits are in front of the decimal in scientific notation?
nikklg [1K]

Answer:

1

Explanation:

How many digits are in front of the decimal in scientific notation?

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